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12 Mar 2021, 03:15
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
60% (01:00) correct
40%
(01:03)
wrong
based on 329
sessions
History
Date
Time
Result
Not Attempted Yet
In how many ways can three different prizes be distributed among six students if no student gets more than one prize ?
(A) 10 ways
(B) 20 ways
(C) 60 ways
(D) 80 ways
(E) 120 ways
(A) 10 ways
(B) 20 ways
(C) 60 ways
(D) 80 ways
(E) 120 ways
24 Mar 2021, 06:09
Kudos
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Bunuel
First \(3\) students need to be chosen, this can be done in \(6c3\) ways\(= 20\)
The Prizes can be distributed to the three students in \(3!\) ways \(= 6\)
So total ways \(6c3 * 3! = 20*6 = 120 \)
Ans-E
Hope it's clear.
General Discussion
25 Jul 2022, 05:00
Kudos
Bookmarks
Bunuel
Let the prizes be p1 , p2 , p3 need to be distributed among six students.
if no student gets more than 1 prize , that means 6 students either get 1 or 0.
so arranging them in 6 places p1,p2,p3,0,0,0.
this can be arranged in 6! and as 0 repeats 3 times , it should be divided by 3!.
6!/3! = 120
