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antoxavier
In measuring the sides of a rectangle, one side is taken 8% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements.

A. 3.5%
B. 2.4%
C. 3%
D. 5%
E. 2.6%

Say both sides of the rectangle are equal to 100 (so consider that we have a square). In this case the area is 100*100=10,000.

Now, the area obtained with wrong measurements would be 108*95=10,260, which is 2.6% greater than the actual area.

Answer: E.
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antoxavier
In measuring the sides of a rectangle, one side is taken 8% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements.

A. 3.5%
B. 2.4%
C. 3%
D. 5%
E. 2.6%

We can let the original area = LW. Thus, the new area is:

1.08L x 0.95W = 1.026LW

Thus, the error percentage is 0.026 = 2.6 percent.

Answer: E
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antoxavier
In measuring the sides of a rectangle, one side is taken 8% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements.

A. 3.5%
B. 2.4%
C. 3%
D. 5%
E. 2.6%

We will take for ease of calculations that length increased and breadth decreased
Excess of 8% in length= (108) l

Deficit in breadth = (095)b

Therefore new area= (1.08) l * (95)b=102.60
Which is difference of 2.6%
E
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