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jcgoodchild
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In one week a construction worker worked more than 40 hours, 18 Mar 2006, 14:31
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In one week a construction worker worked more than 40 hours, and was paid two times his regular hourly rate for every hour worked in excess of 40 hours. If he earned $780, how many hours did he work in that week?

(1) If he had worked 6 more hours that week, his earnings would have been $960.
(2) If he had worked 20 fewer hours that week, his earnings would have been $390 less that week.



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Angela780
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In one week a construction worker worked more than 40 hours, 18 Mar 2006, 17:35
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jcgoodchild
In one week a construction worker worked more than 40 hours, and was paid two times his regular hourly rate for every hour worked in excess of 40 hours. If he earned $780, how many hours did he work in that week?

(1) If he had worked 6 more hours that week, his earnings would have been $960.
(2) If he had worked 20 fewer hours that week, his earnings would have been $390 less that week.
Show more



this is what i figured

1. 6 more hours equals to $ 180 dollars ( 960-780).
per hours is that 180: 6= $ 30 ( overtime). Since it is over time is two times more, the regular hour tarif is $ 15.

He worked 40h *$ 15 = $ 420
He received $ 780 . Overtime is $ 780-$ 420= $ 360 ( 12 hours - $30 p/h)
Total hours worked is 40+12=52
A= sufficient

If this is wrong, cansomebody please explain to me ?
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chuckle
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In one week a construction worker worked more than 40 hours, 19 Mar 2006, 14:34
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I too am for A.
But, I could not prove that B is insuff (I felt it is difficult to prove)... Anyone has any ideazz?? :?:
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bewakoof
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In one week a construction worker worked more than 40 hours, 19 Mar 2006, 15:02
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Angela780
jcgoodchild
In one week a construction worker worked more than 40 hours, and was paid two times his regular hourly rate for every hour worked in excess of 40 hours. If he earned $780, how many hours did he work in that week?

(1) If he had worked 6 more hours that week, his earnings would have been $960.
(2) If he had worked 20 fewer hours that week, his earnings would have been $390 less that week.


this is what i figured

1. 6 more hours equals to $ 180 dollars ( 960-780).
per hours is that 180: 6= $ 30 ( overtime). Since it is over time is two times more, the regular hour tarif is $ 15.
He worked 40h *$ 15 = $ 420
He received $ 780 . Overtime is $ 780-$ 420= $ 360 ( 12 hours - $30 p/h)
Total hours worked is 40+12=52
A= sufficient

If this is wrong, cansomebody please explain to me ?
Show more



how do you know all those 6 hrs.. are overtime??
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conocieur
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In one week a construction worker worked more than 40 hours, 19 Mar 2006, 15:10
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bewakoof
Angela780
jcgoodchild
In one week a construction worker worked more than 40 hours, and was paid two times his regular hourly rate for every hour worked in excess of 40 hours. If he earned $780, how many hours did he work in that week?

(1) If he had worked 6 more hours that week, his earnings would have been $960.
(2) If he had worked 20 fewer hours that week, his earnings would have been $390 less that week.


this is what i figured

1. 6 more hours equals to $ 180 dollars ( 960-780).
per hours is that 180: 6= $ 30 ( overtime). Since it is over time is two times more, the regular hour tarif is $ 15.
He worked 40h *$ 15 = $ 420
He received $ 780 . Overtime is $ 780-$ 420= $ 360 ( 12 hours - $30 p/h)
Total hours worked is 40+12=52
A= sufficient

If this is wrong, cansomebody please explain to me ?


how do you know all those 6 hrs.. are overtime??
Show more


because he worked more than 40 hours and that $780 is his total pay
and about 2 you can have two solutions therefore is not sufficient
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Angela780
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In one week a construction worker worked more than 40 hours, 19 Mar 2006, 18:11
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chuckle
I too am for A.
But, I could not prove that B is insuff (I felt it is difficult to prove)... Anyone has any ideazz?? :?:
Show more


Chuckle I had the same problem, proving that 2 was insuf.
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Angela780
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In one week a construction worker worked more than 40 hours, 19 Mar 2006, 18:12
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Angela780
jcgoodchild
In one week a construction worker worked more than 40 hours, and was paid two times his regular hourly rate for every hour worked in excess of 40 hours. If he earned $780, how many hours did he work in that week?

(1) If he had worked 6 more hours that week, his earnings would have been $960.
(2) If he had worked 20 fewer hours that week, his earnings would have been $390 less that week.


this is what i figured

1. 6 more hours equals to $ 180 dollars ( 960-780).
per hours is that 180: 6= $ 30 ( overtime). Since it is over time is two times more, the regular hour tarif is $ 15.

He worked 40h *$ 15 = $ 420
He received $ 780 . Overtime is $ 780-$ 420= $ 360 ( 12 hours - $30 p/h)
Total hours worked is 40+12=52
A= sufficient

If this is wrong, cansomebody please explain to me ?
Show more



Does anybody else agree with my explanation or am I wrong??
pls discuss
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ywilfred
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In one week a construction worker worked more than 40 hours, 19 Mar 2006, 20:35
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780 = 40*(x) + n(2x)

where x = hourly rate
n = hours in excess of 40 hours

(1) 960 = 40(x) + 6(2x) --> can solve for x and thus solve for n. Sufficient.

(2)
780 = 40*(x) + na(2x)
q = 40*(x) + nb(2x)

We know he earned 780 - 390 = 390 dollars if he works 20 hours less

390 = 40*(x) + nb(2x)
We still have 2 unknown variables that cannot be solved.
Insufficient.

Ans A



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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