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# In the diagram above, B is the center of the larger circle. AB is the

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In the diagram above, B is the center of the larger circle. AB is the  [#permalink]

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28 Jan 2019, 01:23
00:00

Difficulty:

25% (medium)

Question Stats:

73% (01:04) correct 27% (01:23) wrong based on 18 sessions

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In the diagram above, B is the center of the larger circle. AB is the radius of the larger circle and the diameter of the smaller circle. The shaded area is what fraction of the larger circle?

A. 1/8
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Attachment:

GRE exam - In the diagram above, B is the center of the larger circle. .jpg [ 12.44 KiB | Viewed 202 times ]

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In the diagram above, B is the center of the larger circle. AB is the  [#permalink]

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28 Jan 2019, 01:33
AB is the diameter of the smaller circle.
Area = $$\frac{π*AB^2}{4}$$

The radius of bigger circle = AB
Area of the bigger circle = $$π*AB^2$$
Area of the shaded portion = Area of the bigger circle - Area of the smaller circle
$$π*AB^2$$ - $$\frac{π*AB^2}{4}$$
$$\frac{3AB^2}{4}$$ = Shaded area

Now,
$$\frac{3πAB^2}{4}$$/$$πAB^2$$ = 3/4

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Re: In the diagram above, B is the center of the larger circle. AB is the  [#permalink]

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28 Jan 2019, 03:09
Bunuel wrote:

In the diagram above, B is the center of the larger circle. AB is the radius of the larger circle and the diameter of the smaller circle. The shaded area is what fraction of the larger circle?

A. 1/8
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Attachment:
GRE exam - In the diagram above, B is the center of the larger circle. .jpg

let AB = 4
so area of larger circle ; 16pi
and small circle ; 4pi
shaded area = 16-4 = 12 pi
ratio
12pi/16pi ; 3/4
IMO E
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Re: In the diagram above, B is the center of the larger circle. AB is the   [#permalink] 28 Jan 2019, 03:09
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