In the diagram above, points A, B, C, D, and E represent the

Question

https://gmatclub.com/forum/download/file.php?id=17252 In the diagram above, points A, B, C, D, and E represent the five teams in a certain league in which each team must play each of the other teams exactly once. The segments connecting pairs of points indicate that the two corresponding teams have already played their game. The arrows on the segments point to the teams that lost; the lack of an arrow on a segment indicates that the game ended in a tie. After all games have been played, which of the following could NOT be the percent of games played that ended in a tie? A. 10% B. 20% C. 30% D. 40% E. 50% TEam.jpg

raingary · Accepted Answer

Out of the 7 matches displayed in the diagram 2 are ties (AC,ED).

Total matches to be played = 5C2 = 10

Remaining matches to be played= 10-7 =3

the maximum ties that can happen = 2+3 =5 
minimum ties that can happen =2

So , percentage of minimum ties = (2/10) *100 =20%

Hence ,A is the answer as 10% is not possible.

shashankism · Answer

Total games possible between teams = 5C2 = 10 
Total games played = 7 
Total games already ended up in tie = 2
Total games left to be played = 3

So, Maximum games that can end in tie = 5
Minimum games that can end in tie = 2

So,Maxm percentage of game that can end in a tie = 50%
Minm percentage of game that can end in a tie = 20%

Hence option A is the answer.

b2bt · Answer

Doesn't look like a 700+ question

ramannanda9 · Answer

Yes, but the key is too just take out the minimum percentage that is possible, which in this case is 20% and be done with it.

Poorvasha · Answer

Total number of matches = 5C2= 10
From the figure, we can see that the minimum number of ties are 2.
So, option A (1/10*100= 10%) is ruled out for sure.

Hence, answer is A.

Basshead · Answer

The diagram can appear a little intimidating at first but it's simply telling us that 7 games have been played (2 of which ended in a draw)

5C2: 10 games

7 games have ALREADY been played. This means we have 3 games left to be played.

The 3 games may or may not end in a draw. We already know 2 games ended in a draw. So at a minimum after 10 games, 2 will end in a draw. At a maximum after 10 games, 5 will end in a draw.

Answer: 10% (1 out of 10 games in a draw) is not possible as we already know for a fact that 2 games ended in a draw.

ChandlerBong · Answer

Hi KarishmaB , Can you please share your approach to this question? Thanks in advance.

KarishmaB · Answer

5 teams - each has to play all the others once

Hence total number of games played will be 5C2 = 10

We have data on 7 games - 2 of those were a tie. We don't know about the other 3 games. 
Then, of the 10 games, minimum 2 and maximum 5 could have been a tie.

Hence, the percentage of tie games would be from 20% to 50%.

Answer (A)

corrayatom · Answer

Total games 4+3+2+1 = 10
2 already tied. So, 2/10 =0.2 = 20%
It can increase in future, but not decrease. So ans is A.

In the diagram above, points A, B, C, D, and E represent the

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In the diagram above, points A, B, C, D, and E represent the

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