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24 Mar 2022, 04:15
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
96% (00:57) correct
4%
(01:39)
wrong
based on 90
sessions
History
Date
Time
Result
Not Attempted Yet
In the equation mx + 5 = y, m is a constant. If x = 2 when y = 1, when is the value of x when y = –1?
A. −1
B. 0
C. 1
D. 2
E. 3
A. −1
B. 0
C. 1
D. 2
E. 3
24 Mar 2022, 04:38
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y = mx + 5 is a line with slope m, and y-intercept 5, so the point (0, 5) is on the line. We're also told (2, 1) is on the line, so the line is falling as you move to the right. The point where y = -1 must therefore be to the right of the point (2, 1), and its x-coordinate must therefore be greater than 2, and the only plausible answer is 3, answer E. Or you could do a bit more work to learn m = -2 and substitute.
27 Sep 2023, 01:26
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Bunuel
Solution:
- Given \(y=mx+5\)
- \(x=2\) and \(y=1\)
- \(⇒1=2m+5\)
- So, when \(y=-1\)
- \(⇒-1=-2x+5\)
\(⇒x=3\)
Hence the right answer is Option E
