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In the figure, AB and CD are the diameters of the circle. What is the

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In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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New post 11 Oct 2018, 02:13
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A
B
C
D
E

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In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°


Attachment:
circle.jpg
circle.jpg [ 36.55 KiB | Viewed 416 times ]

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Re: In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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New post 11 Oct 2018, 02:53
Bunuel wrote:
Image
In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°


Attachment:
circle.jpg



AB and CD are diameters. AC and DB are parallel.

Thus , d = 32 degree.

x = 32 degree . As d = x.


The best answer is D.
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In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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New post Updated on: 11 Oct 2018, 07:19
In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°


Attachment:
circle.jpg
[/quote]


Answer must be D.
As two radius for isosceles triangle, hence angle d will also be 32, and both cords are parallel, so angle x must be equal to d hence answer is 32
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Originally posted by bashdeep on 11 Oct 2018, 03:07.
Last edited by bashdeep on 11 Oct 2018, 07:19, edited 1 time in total.
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Re: In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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New post 11 Oct 2018, 07:04
Bunuel wrote:
Image
In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°


Attachment:
circle.jpg


\(OC = OA = OD = OB = Radius\)

\(∠OAC = ∠OCA = ∠ODB = ∠OBD = 32° = x°\) (Vertically Opposite Angle)

Thus, Answer must be (D) 32°
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Re: In the figure, AB and CD are the diameters of the circle. What is the   [#permalink] 11 Oct 2018, 07:04
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