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In the figure, AB and CD are the diameters of the circle. What is the

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Joined: 02 Sep 2009
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In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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11 Oct 2018, 02:13
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25% (medium)

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In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°

Attachment:

circle.jpg [ 36.55 KiB | Viewed 416 times ]

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Joined: 31 Oct 2013
Posts: 1163
Concentration: Accounting, Finance
GPA: 3.68
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Re: In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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11 Oct 2018, 02:53
Bunuel wrote:

In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°

Attachment:
circle.jpg

AB and CD are diameters. AC and DB are parallel.

Thus , d = 32 degree.

x = 32 degree . As d = x.

The best answer is D.
Intern
Joined: 03 Sep 2018
Posts: 22
WE: Analyst (Consulting)
In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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Updated on: 11 Oct 2018, 07:19
In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°

Attachment:
circle.jpg
[/quote]

Answer must be D.
As two radius for isosceles triangle, hence angle d will also be 32, and both cords are parallel, so angle x must be equal to d hence answer is 32
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Bashdeep

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Originally posted by bashdeep on 11 Oct 2018, 03:07.
Last edited by bashdeep on 11 Oct 2018, 07:19, edited 1 time in total.
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Re: In the figure, AB and CD are the diameters of the circle. What is the  [#permalink]

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11 Oct 2018, 07:04
Bunuel wrote:

In the figure, AB and CD are the diameters of the circle. What is the value of x ?

(A) 16°
(B) 18°
(C) 26°
(D) 32°
(E) 58°

Attachment:
circle.jpg

$$OC = OA = OD = OB = Radius$$

$$∠OAC = ∠OCA = ∠ODB = ∠OBD = 32° = x°$$ (Vertically Opposite Angle)

Thus, Answer must be (D) 32°
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Thanks and Regards

Abhishek....

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Re: In the figure, AB and CD are the diameters of the circle. What is the   [#permalink] 11 Oct 2018, 07:04
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