GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 07 Dec 2019, 06:46

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5,

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 59589
In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5,  [#permalink]

### Show Tags

02 Apr 2019, 23:25
1
1
00:00

Difficulty:

15% (low)

Question Stats:

88% (01:57) correct 13% (02:29) wrong based on 32 sessions

### HideShow timer Statistics

In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5, and y = 10, then what is the area of ∆AFD ?

(A) 2.5

(B) 5

(C) 12.5

(D) 50

(E) 50 + 5y

Attachment:

#GREpracticequestion In the figure, ABCD.jpg [ 20.56 KiB | Viewed 491 times ]

_________________
NUS School Moderator
Joined: 18 Jul 2018
Posts: 1024
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5,  [#permalink]

### Show Tags

03 Apr 2019, 12:03
1
AD = BC = CE = x = 5
AB = CD = y = 10
Then, BE = $$5\sqrt{2}$$ (45-45-90 triangle) = AF
Now, FD = $$\sqrt{50-25}$$ = 5
Area of AFD = 1/2*5*5 = 12.5

Director
Joined: 27 May 2012
Posts: 945
Re: In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5,  [#permalink]

### Show Tags

06 Apr 2019, 13:27
Bunuel wrote:

In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5, and y = 10, then what is the area of ∆AFD ?

(A) 2.5

(B) 5

(C) 12.5

(D) 50

(E) 50 + 5y

Attachment:
#GREpracticequestion In the figure, ABCD.jpg

Alternate Soln.
$$\Delta ADF \,\, and \,\,\Delta BCE\, are\,\, similar \\ AD=BC=5\\ DF=CE=5\\ Area \,\,of \,\Delta ADF \Rightarrow \frac{1}{2}*5*5 =12.5$$
_________________
- Stne
Manager
Joined: 31 Dec 2018
Posts: 114
Location: India
Re: In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5,  [#permalink]

### Show Tags

06 Apr 2019, 21:37
tri.ADF and tri.BCE are congruent by AAA property.
Hence, sides will be equal in length.

Area = 25/2= 12.5

Posted from my mobile device
Re: In the figure, ABCD is a rectangle and AF is parallel to BE. If x = 5,   [#permalink] 06 Apr 2019, 21:37
Display posts from previous: Sort by