It is currently 21 Oct 2017, 14:36

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In the figure above, a circular hoop is rolling along a flat

Author Message
TAGS:

### Hide Tags

Director
Joined: 29 Nov 2012
Posts: 868

Kudos [?]: 1413 [1], given: 543

In the figure above, a circular hoop is rolling along a flat [#permalink]

### Show Tags

17 Sep 2013, 01:09
1
KUDOS
00:00

Difficulty:

15% (low)

Question Stats:

74% (01:03) correct 26% (00:57) wrong based on 99 sessions

### HideShow timer Statistics

Attachment:

wheel.jpg [ 3.41 KiB | Viewed 1840 times ]
In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in
[Reveal] Spoiler: OA

_________________

Click +1 Kudos if my post helped...

Amazing Free video explanation for all Quant questions from OG 13 and much more http://www.gmatquantum.com/og13th/

GMAT Prep software What if scenarios http://gmatclub.com/forum/gmat-prep-software-analysis-and-what-if-scenarios-146146.html

Last edited by Bunuel on 17 Sep 2013, 01:18, edited 1 time in total.
Edited the question and the tags.

Kudos [?]: 1413 [1], given: 543

Math Expert
Joined: 02 Sep 2009
Posts: 41892

Kudos [?]: 129158 [0], given: 12194

In the figure above, a circular hoop is rolling along a flat [#permalink]

### Show Tags

17 Sep 2013, 01:17

In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in

We are basically given that the circumference of the circle is 25 inches --> $$2\pi{r}=25$$ --> $$r=\frac{25}{2\pi}\approx{\frac{25}{6.28}}\approx{4}$$.

_________________

Last edited by Engr2012 on 03 Aug 2015, 13:42, edited 1 time in total.
Corrected the typo.

Kudos [?]: 129158 [0], given: 12194

Senior Manager
Joined: 02 Dec 2014
Posts: 373

Kudos [?]: 90 [0], given: 349

Location: Russian Federation
Concentration: General Management, Economics
GMAT 1: 640 Q44 V33
WE: Sales (Telecommunications)
Re: In the figure above, a circular hoop is rolling along a flat [#permalink]

### Show Tags

03 Aug 2015, 13:30
Bunuel wrote:

In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in

We are basically given that the circumference of the circle is 24 inches --> $$2\pi{r}=25$$ --> $$r=\frac{25}{2\pi}\approx{\frac{25}{6.28}}\approx{4}$$.

Bunuel! I think you meant 25 inch not 24 (bold part). Thanks!
_________________

"Are you gangsters?" - "No we are Russians!"

Kudos [?]: 90 [0], given: 349

Math Forum Moderator
Joined: 20 Mar 2014
Posts: 2675

Kudos [?]: 1728 [0], given: 792

Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: In the figure above, a circular hoop is rolling along a flat [#permalink]

### Show Tags

03 Aug 2015, 13:43
Konstantin1983 wrote:
Bunuel wrote:

In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in

We are basically given that the circumference of the circle is 24 inches --> $$2\pi{r}=25$$ --> $$r=\frac{25}{2\pi}\approx{\frac{25}{6.28}}\approx{4}$$.

Bunuel! I think you meant 25 inch not 24 (bold part). Thanks!

Thanks, post updated.
_________________

Thursday with Ron updated list as of July 1st, 2015: http://gmatclub.com/forum/consolidated-thursday-with-ron-list-for-all-the-sections-201006.html#p1544515
Inequalities tips: http://gmatclub.com/forum/inequalities-tips-and-hints-175001.html
Debrief, 650 to 750: http://gmatclub.com/forum/650-to-750-a-10-month-journey-to-the-score-203190.html

Kudos [?]: 1728 [0], given: 792

Veritas Prep GMAT Instructor
Joined: 15 Jul 2015
Posts: 110

Kudos [?]: 76 [0], given: 7

GPA: 3.62
WE: Corporate Finance (Consulting)
Re: In the figure above, a circular hoop is rolling along a flat [#permalink]

### Show Tags

03 Aug 2015, 18:53
If Point A on the hoop leaves a mark every 25 inches, the hoop has a Circumference of 25. The formula for Circumference is 2 pi r. Since the question is asking for the radius, we can calculate it. 25 = 2 pi r ==> 12.5 = pi r ==> 12.5/pi = r

If we approximate pi as 3, r is approximately 4.

_________________

Dennis
Veritas Prep | GMAT Instructor

Get started with Veritas Prep GMAT On Demand for \$199

Veritas Prep Reviews

Kudos [?]: 76 [0], given: 7

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16587

Kudos [?]: 273 [0], given: 0

Re: In the figure above, a circular hoop is rolling along a flat [#permalink]

### Show Tags

07 Aug 2017, 21:00
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 273 [0], given: 0

Re: In the figure above, a circular hoop is rolling along a flat   [#permalink] 07 Aug 2017, 21:00
Display posts from previous: Sort by