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# In the figure above, a circular hoop is rolling along a flat

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In the figure above, a circular hoop is rolling along a flat  [#permalink]

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Updated on: 17 Sep 2013, 01:18
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82% (01:16) correct 18% (01:34) wrong based on 106 sessions

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In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in

Originally posted by fozzzy on 17 Sep 2013, 01:09.
Last edited by Bunuel on 17 Sep 2013, 01:18, edited 1 time in total.
Edited the question and the tags.
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In the figure above, a circular hoop is rolling along a flat  [#permalink]

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Updated on: 03 Aug 2015, 13:42

In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in

We are basically given that the circumference of the circle is 25 inches --> $$2\pi{r}=25$$ --> $$r=\frac{25}{2\pi}\approx{\frac{25}{6.28}}\approx{4}$$.

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Originally posted by Bunuel on 17 Sep 2013, 01:17.
Last edited by ENGRTOMBA2018 on 03 Aug 2015, 13:42, edited 1 time in total.
Corrected the typo.
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Re: In the figure above, a circular hoop is rolling along a flat  [#permalink]

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03 Aug 2015, 13:30
Bunuel wrote:

In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in

We are basically given that the circumference of the circle is 24 inches --> $$2\pi{r}=25$$ --> $$r=\frac{25}{2\pi}\approx{\frac{25}{6.28}}\approx{4}$$.

Bunuel! I think you meant 25 inch not 24 (bold part). Thanks!
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Re: In the figure above, a circular hoop is rolling along a flat  [#permalink]

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03 Aug 2015, 13:43
Konstantin1983 wrote:
Bunuel wrote:

In the figure above, a circular hoop is rolling along a flat surface in a straight line. If point A touches the surface at 25-inch intervals, then the radius of the hoop is approximately

A) 8 in
B) 7 in
C) 6 in
D) 5 in
E) 4 in

We are basically given that the circumference of the circle is 24 inches --> $$2\pi{r}=25$$ --> $$r=\frac{25}{2\pi}\approx{\frac{25}{6.28}}\approx{4}$$.

Bunuel! I think you meant 25 inch not 24 (bold part). Thanks!

Thanks, post updated.
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Re: In the figure above, a circular hoop is rolling along a flat  [#permalink]

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03 Aug 2015, 18:53
If Point A on the hoop leaves a mark every 25 inches, the hoop has a Circumference of 25. The formula for Circumference is 2 pi r. Since the question is asking for the radius, we can calculate it. 25 = 2 pi r ==> 12.5 = pi r ==> 12.5/pi = r

If we approximate pi as 3, r is approximately 4.

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Re: In the figure above, a circular hoop is rolling along a flat  [#permalink]

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07 Aug 2017, 21:00
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Re: In the figure above, a circular hoop is rolling along a flat   [#permalink] 07 Aug 2017, 21:00
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