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In the figure above, a circular hoop is rolling along a flat surface

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Math Expert
Joined: 02 Sep 2009
Posts: 50000
In the figure above, a circular hoop is rolling along a flat surface  [#permalink]

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14 Nov 2017, 23:49
00:00

Difficulty:

25% (medium)

Question Stats:

85% (01:03) correct 15% (01:31) wrong based on 26 sessions

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In the figure above, a circular hoop is rolling along a flat surface on a straight line. If point A touches the surface at 25 inch intervals, then the radius of the hoop is approximately

(A) 8 inches
(B) 7 inches
(C) 6 inches
(D) 5 inches
(E) 4 inches

Attachment:

2017-11-15_1036_003.png [ 3.84 KiB | Viewed 604 times ]

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Joined: 05 Dec 2016
Posts: 246
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: In the figure above, a circular hoop is rolling along a flat surface  [#permalink]

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15 Nov 2017, 03:41
2pr=25
pr=25/2
r=25/(2*3,14)=25/6,28~4
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Joined: 09 Mar 2017
Posts: 529
Location: India
Concentration: Marketing, Organizational Behavior
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Re: In the figure above, a circular hoop is rolling along a flat surface  [#permalink]

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15 Nov 2017, 09:34
Bunuel wrote:

In the figure above, a circular hoop is rolling along a flat surface on a straight line. If point A touches the surface at 25 inch intervals, then the radius of the hoop is approximately

(A) 8 inches
(B) 7 inches
(C) 6 inches
(D) 5 inches
(E) 4 inches

Attachment:
2017-11-15_1036_003.png

point A makes complete revolutions in 25 inch interval.
Circumference = 2*pi*r = 25
r = 4 inches approx.

E
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Re: In the figure above, a circular hoop is rolling along a flat surface &nbs [#permalink] 15 Nov 2017, 09:34
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