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# In the figure above, a square with side of length 3 is inscribed in a

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Math Expert
Joined: 02 Sep 2009
Posts: 58322
In the figure above, a square with side of length 3 is inscribed in a  [#permalink]

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26 Feb 2019, 01:18
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Difficulty:

15% (low)

Question Stats:

86% (01:29) correct 14% (01:21) wrong based on 43 sessions

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In the figure above, a square with side of length 3 is inscribed in a circle that is inscribed in a square. What is the area of the larger square?

A. 14
B. 15
C. 16
D. 18
E. 20

Attachment:

2019-02-26_1209.png [ 18.98 KiB | Viewed 488 times ]

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Joined: 31 Dec 2018
Posts: 115
Location: India
Re: In the figure above, a square with side of length 3 is inscribed in a  [#permalink]

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26 Feb 2019, 02:14
Length of diagonal of inner square is 3✓2.
Length of the diagonal is equal to the diameter of the circle is equal to the side of the outer square.
A=(3√2)^2=18

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Re: In the figure above, a square with side of length 3 is inscribed in a  [#permalink]

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26 Feb 2019, 02:18
1
Bunuel wrote:

In the figure above, a square with side of length 3 is inscribed in a circle that is inscribed in a square. What is the area of the larger square?

A. 14
B. 15
C. 16
D. 18
E. 20

Attachment:
2019-02-26_1209.png

Diagonal of smaller square= Diameter of circle = Side of bigger square = 3sqrt(2)

Area of bigger square = (3sqrt(2))^2 = 18

Hence D
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Re: In the figure above, a square with side of length 3 is inscribed in a  [#permalink]

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26 Feb 2019, 02:37
diagonal of small square = diameter of circle = length of large square
3√2; squaring it we get area of large square = 18
IMO D

Bunuel wrote:

In the figure above, a square with side of length 3 is inscribed in a circle that is inscribed in a square. What is the area of the larger square?

A. 14
B. 15
C. 16
D. 18
E. 20

Attachment:
2019-02-26_1209.png

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Re: In the figure above, a square with side of length 3 is inscribed in a  [#permalink]

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26 Feb 2019, 05:29
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Posts: 8043
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Re: In the figure above, a square with side of length 3 is inscribed in a  [#permalink]

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01 Mar 2019, 10:50
Bunuel wrote:

In the figure above, a square with side of length 3 is inscribed in a circle that is inscribed in a square. What is the area of the larger square?

A. 14
B. 15
C. 16
D. 18
E. 20

Attachment:
2019-02-26_1209.png

Diagonal of smaller square = diameter of circle = side of larger square = 3√2.

So the area of the larger square is (3√2)^2 = 9 x 2 = 18.

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Re: In the figure above, a square with side of length 3 is inscribed in a   [#permalink] 01 Mar 2019, 10:50
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