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# In the figure above, all streets run in straight lines. If the angle

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Math Expert
Joined: 02 Sep 2009
Posts: 51123
In the figure above, all streets run in straight lines. If the angle  [#permalink]

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22 Feb 2018, 20:07
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Difficulty:

15% (low)

Question Stats:

97% (01:08) correct 3% (03:30) wrong based on 47 sessions

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In the figure above, all streets run in straight lines. If the angle of intersection of Avenue Foche and Victor Hugo Street is 90° and Avenue Foche is parallel to St. Michael's Boulevard, then what is the area of the shaded portion of the figure (expressed in square feet)?

(A) 600

(B) 750

(C) 1350

(D) 2400

(E) 3750

Attachment:

2018-02-23_0806.png [ 58.37 KiB | Viewed 577 times ]

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Re: In the figure above, all streets run in straight lines. If the angle  [#permalink]

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22 Feb 2018, 20:25
Attachment:

2018-02-23_0806.png [ 56.54 KiB | Viewed 461 times ]

Area of the shaded region is the sum of the area of the rectangle and the area of the right-angled triangle

Area of rectangle = $$20*30 = 600$$
Area of triangle = $$\frac{1}{2}*50*30 = 25*30 = 750$$

Therefore, the area of the shaded region is $$600 + 750 = 1350$$(Option C)
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Re: In the figure above, all streets run in straight lines. If the angle  [#permalink]

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22 Feb 2018, 22:50
We can split the image into 2 areas, one rectangle and one triangle.

Area of rectangle = 30 * 20 = 600
Are of triangle= (50*30)/2 = 750

Ans: C
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Re: In the figure above, all streets run in straight lines. If the angle  [#permalink]

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22 Feb 2018, 23:49
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Bunuel wrote:

In the figure above, all streets run in straight lines. If the angle of intersection of Avenue Foche and Victor Hugo Street is 90° and Avenue Foche is parallel to St. Michael's Boulevard, then what is the area of the shaded portion of the figure (expressed in square feet)?

(A) 600

(B) 750

(C) 1350

(D) 2400

(E) 3750

Attachment:
2018-02-23_0806.png

Area of a trapezoid = (1/2) * (Sum of bases) * height = (1/2)*(20 + 70)*30 = 1350

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Re: In the figure above, all streets run in straight lines. If the angle  [#permalink]

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23 Feb 2018, 00:48
Bunuel wrote:

In the figure above, all streets run in straight lines. If the angle of intersection of Avenue Foche and Victor Hugo Street is 90° and Avenue Foche is parallel to St. Michael's Boulevard, then what is the area of the shaded portion of the figure (expressed in square feet)?

(A) 600

(B) 750

(C) 1350

(D) 2400

(E) 3750

Attachment:
2018-02-23_0806.png

20x30 = 600

70-20 = 50

h= 30

area of triangle = 1/2 x 30 x 50 = 750

750+600 = 1350

(C) imo
Re: In the figure above, all streets run in straight lines. If the angle &nbs [#permalink] 23 Feb 2018, 00:48
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