Last visit was: 20 May 2026, 00:51 It is currently 20 May 2026, 00:51
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
555-605 (Medium)|   Geometry|      
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 May 2026
Posts: 110,713
Own Kudos:
815,832
 [13]
Given Kudos: 106,325
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,713
Kudos: 815,832
 [13]
In the figure above, if AD is parallel to BC, then ∠ADC = 23 Jul 2020, 05:28
Kudos
Add Kudos
12
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

35% (medium)

Question Stats:

71% (02:09) correct 29% (02:35) wrong based on 170 sessions

History

Date
Time
Result
Not Attempted Yet

In the figure above, if AD is parallel to BC, then \(∠ADC = \)

A. 11°

B. 22°

C. 33°

D. 46°

E. 134°

Show Spoiler
Attachment:
1.jpg
1.jpg [ 21.84 KiB | Viewed 6389 times ]
ShowHide Answer
Official Answer
C
User avatar
CrackverbalGMAT
User avatar
Major Poster
Joined: 03 Oct 2013
Last visit: 19 May 2026
Posts: 4,849
Own Kudos:
9,207
Given Kudos: 227
Affiliations: CrackVerbal
Location: India
Expert
Expert reply
Posts: 4,849
Kudos: 9,207
In the figure above, if AD is parallel to BC, then ∠ADC = 23 Jul 2020, 05:42
Kudos
Add Kudos
Bookmarks
Bookmark this Post
In Triangle BEC, \(\angle BCE\) = 180 - x - 44 = 136 - x (Sum of angles of a triangle = \(180^o\))

Since AD is parallel BC, \(\angle ADC\) + \(\angle BCD\) = \(180^o\) (Sum of interior angles between 2 parallel lines cut by a transversal = \(180^o\))

3x + 2x + 136 - x = 180

4x = 44

x = 11

\(\angle ADC\) = 3x = 3*11 = \(33^o\)

Option C

Arun Kumar
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 19 May 2026
Posts: 7,034
Own Kudos:
17,009
 [1]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
My Reviews
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 7,034
Kudos: 17,009
 [1]
In the figure above, if AD is parallel to BC, then ∠ADC = 23 Jul 2020, 05:47
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, if AD is parallel to BC, then \(∠ADC = \)

A. 11°

B. 22°

C. 33°

D. 46°

E. 134°

Show Spoiler
Attachment:
1.jpg
Show more

Angle ADC = 3x = ?

Angle BCE = 180 - (X+44) = 136-x

Also, Angle BCD + Angle CDA = 180o (Parallel lines)

i.e. (136-x)+2x+3x = 180

i.e. 4x = 44
i.e. x = 11

hence, Angle ADC = 3x = 3*11 = 33o



Answer: Option C
User avatar
v12345
User avatar
Joined: 01 Mar 2015
Last visit: 10 May 2026
Posts: 398
Own Kudos:
1,121
Given Kudos: 44
Location: India
Posts: 398
Kudos: 1,121
In the figure above, if AD is parallel to BC, then ∠ADC = 23 Jul 2020, 08:22
Kudos
Add Kudos
Bookmarks
Bookmark this Post
We have, 180 - x - 44 + 2x + 3x = 180
=> 4x - 44 = 0
=> x = 11
ADC = 3x = 33

Hence, OA is (C).
avatar
Getsome2
avatar
Joined: 14 Apr 2018
Last visit: 04 Oct 2023
Posts: 12
Own Kudos:
4
Given Kudos: 32
Posts: 12
Kudos: 4
In the figure above, if AD is parallel to BC, then ∠ADC = 23 Jul 2020, 13:26
Kudos
Add Kudos
Bookmarks
Bookmark this Post
From the problem drawing, we can tell Angle ADC must be a multiple of 3

Taking a quick look at the answer choices, there's only one answer which fits

Thus, x must be 11 and angle ADC equals 33

IMO C
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 19 May 2026
Posts: 22,352
Own Kudos:
26,595
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,352
Kudos: 26,595
In the figure above, if AD is parallel to BC, then ∠ADC = 26 Jul 2020, 17:06
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, if AD is parallel to BC, then \(∠ADC = \)

A. 11°

B. 22°

C. 33°

D. 46°

E. 134°

Show Spoiler
Attachment:
1.jpg
Show more

Solution:

Letting angle BCE = y, we have:

(y + 2x) + 3x = 180 (since consecutive angles of a parallelogram add up to 180 degrees)

and

y + x + 44 = 180 (since the sum of the measures of the 3 angles of a triangle is 180 degrees)

Since the right hand sides of both equations above is 180, we can set the left hand sides equal to each other.

(y + 2x) + 3x = y + x + 44

5x = x + 44

4x = 44

x = 11

Since angle ADC = 3x, angle ADC = 3(11) = 33 degrees.

Answer: C
User avatar
BrentGMATPrepNow
User avatar
Major Poster
Joined: 12 Sep 2015
Last visit: 31 Oct 2025
Posts: 6,733
Own Kudos:
36,598
 [1]
Given Kudos: 799
Location: Canada
Expert
Expert reply
Posts: 6,733
Kudos: 36,598
 [1]
In the figure above, if AD is parallel to BC, then ∠ADC = 28 Nov 2021, 07:47
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, if AD is parallel to BC, then \(∠ADC = \)

A. 11°

B. 22°

C. 33°

D. 46°

E. 134°

Show Spoiler
Attachment:
1.jpg
Show more

First, since angles in a triangle must add to 180°, we can see that the missing angle in the red triangle must be 180° - (x + 44)°



Simplify this measurement to get (136 - x)°



Finally, since AD is parallel to BC, we know that the two highlighted angles below must add to 180°.


So, we can write: (136 - x)° + 2x° + 3x° = 180°
Simplify: 136 + 4x = 180
Subtract 136 from both sides: : 4x = 44
Solve: x = 11

Our goal is to find the measurement of ∠ADC
Since ∠ADC = 3x°, we can replace x with 11 to get: ∠ADC = 3x° = 3(11)° = 33°

Answer: C
avatar
dhruvsharma2117
avatar
Joined: 28 Aug 2022
Last visit: 08 May 2024
Posts: 56
Own Kudos:
22
Given Kudos: 25
Location: India
Concentration: Operations, Strategy
Schools: IIM (S)
GMAT 1: 540 Q39 V27
GRE 1: Q157 V150
GPA: 2.3
WE:Operations (Manufacturing)
Schools: IIM (S)
GMAT 1: 540 Q39 V27
GRE 1: Q157 V150
Posts: 56
Kudos: 22
In the figure above, if AD is parallel to BC, then ∠ADC = 05 Feb 2023, 20:55
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Please find the solution for the question
Attachments

File comment: Please find my solution
WhatsApp Image 2023-02-06 at 09.19.33.jpeg
WhatsApp Image 2023-02-06 at 09.19.33.jpeg [ 88.72 KiB | Viewed 2314 times ]

User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 20 May 2026
Posts: 6,006
Own Kudos:
5,879
Given Kudos: 163
Location: India
Schools: HBS '26 CBS '26 Wharton '26
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
My Reviews
Schools: HBS '26 CBS '26 Wharton '26
GMAT 1: 690 Q50 V34
Posts: 6,006
Kudos: 5,879
In the figure above, if AD is parallel to BC, then ∠ADC = 06 Feb 2023, 02:21
Kudos
Add Kudos
Bookmarks
Bookmark this Post

In the figure above, if AD is parallel to BC, then \(∠ADC = \)

3x + 2x + (180 - x - 44) = 180
4x = 44
\(∠ADC = 3x = 33 \)

IMO C
Moderators:
Bunuel
Math Expert
110713 posts
Krunaal
Tuck School Moderator
852 posts