May 24 10:00 PM PDT  11:00 PM PDT Join a FREE 1day workshop and learn how to ace the GMAT while keeping your fulltime job. Limited for the first 99 registrants. May 25 07:00 AM PDT  09:00 AM PDT Attend this webinar and master GMAT SC in 10 days by learning how meaning and logic can help you tackle 700+ level SC questions with ease. May 27 01:00 AM PDT  11:59 PM PDT All GMAT Club Tests are free and open on May 27th for Memorial Day! May 27 10:00 PM PDT  11:00 PM PDT Special savings are here for Magoosh GMAT Prep! Even better  save 20% on the plan of your choice, now through midnight on Tuesday, 5/27 May 30 10:00 PM PDT  11:00 PM PDT Application deadlines are just around the corner, so now’s the time to start studying for the GMAT! Start today and save 25% on your GMAT prep. Valid until May 30th. Jun 01 07:00 AM PDT  09:00 AM PDT Learn reading strategies that can help even nonvoracious reader to master GMAT RC
Author 
Message 
Intern
Status: UF BSBA '15  Preparing for the future
Joined: 09 May 2011
Posts: 24
Location: United States
GPA: 3.87
WE: Human Resources (Consulting)

In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
Show Tags
Updated on: 23 Jun 2011, 20:27
Question Stats:
71% (00:18) correct 29% (01:08) wrong based on 7 sessions
HideShow timer Statistics
In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD? (1) Angle DAB = 45 degrees (2) Angle ADC + angle BCD = 205 degrees Hello. I am doing the PR1012, and I came across this question. I got it wrong to begin with, but I also do not understand their brief explanation. Please help me. Just for the record I am in the college class of 2015, but I need to take the GMAT before the end of my sophomore year for a combined degree program (shooting for 700; I know it is really hard!). Eventually I may want an MBA, though. I am studying now to ease into it. I am pretty smart for the most part, but I do badly on tests. I got a 1380 SAT (670M, 710CR) with a little studying. Anyway, here is the question. After one day of studying I already hate the data questions. In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD? 1. Angle DAB = 45 degrees 2. Angle ADC + angle BCD = 205 degrees OPEN DISCUSSION OF THIS QUESTION IS HERE: thisdsijustcannotfigureoutiamgettinge99063.html== Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
Official Answer and Stats are available only to registered users. Register/ Login.
Originally posted by jw on 23 Jun 2011, 14:31.
Last edited by jw on 23 Jun 2011, 20:27, edited 1 time in total.



Senior Manager
Joined: 24 Mar 2011
Posts: 341
Location: Texas

Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
Show Tags
23 Jun 2011, 15:10
st2 is fairly simple to get BCD  ADE, so st is sufficient.
as per st 1, BCD = 36011010045DAE BCD = 105DAE
for triangle ADE, DAE = 180100ADE DAE = 80ADE
combining both eqns, BCD = 10580+ADE ==> BCD  ADE = 25 sufficient.



Intern
Status: UF BSBA '15  Preparing for the future
Joined: 09 May 2011
Posts: 24
Location: United States
GPA: 3.87
WE: Human Resources (Consulting)

Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
Show Tags
23 Jun 2011, 22:47
My apologies for misposting.
Please move this to the data sufficiency forum.



Intern
Joined: 08 Mar 2011
Posts: 9

Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
Show Tags
24 Jun 2011, 13:28
St 2 is very simple, as discussed in the above post. But I solved the first stmt like below, I hope it'll help you! Let <BCD = y; <ADE = x; therefore <CDA = 180  x (since, <CDA and <ADE are supplimentary)
Now sum of angles of quadrilateral ABCD is 360; <DAB + <ABC + <BCD + <CDA = 360 => 45 + 110 + Y + 180  X = 360
You can get the difference b/t y and X which is the answer for the question. Therefore the answer is D



Intern
Status: UF BSBA '15  Preparing for the future
Joined: 09 May 2011
Posts: 24
Location: United States
GPA: 3.87
WE: Human Resources (Consulting)

Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
Show Tags
24 Jun 2011, 14:39
I still do not see how statement two is so simple.



Retired Moderator
Joined: 20 Dec 2010
Posts: 1772

Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
Show Tags
24 Jun 2011, 14:50
jw wrote: I still do not see how statement two is so simple. Sum of angles in a straight line is 180. ADE+ADC=180 ADC=180ADE 1 2. ADC + BCD = 205 Substitute ADC from 1 180ADE+BCD=205 BCDADE=205180=25 BCDADE is nothing but the difference asked in the question stem. Sufficient.
_________________



Math Expert
Joined: 02 Sep 2009
Posts: 55271

Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
Show Tags
14 Aug 2017, 03:18
jw wrote: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD? (1) Angle DAB = 45 degrees (2) Angle ADC + angle BCD = 205 degrees Hello. I am doing the PR1012, and I came across this question. I got it wrong to begin with, but I also do not understand their brief explanation. Please help me. Just for the record I am in the college class of 2015, but I need to take the GMAT before the end of my sophomore year for a combined degree program (shooting for 700; I know it is really hard!). Eventually I may want an MBA, though. I am studying now to ease into it. I am pretty smart for the most part, but I do badly on tests. I got a 1380 SAT (670M, 710CR) with a little studying. Anyway, here is the question. After one day of studying I already hate the data questions. In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD? 1. Angle DAB = 45 degrees 2. Angle ADC + angle BCD = 205 degrees Important property of polygons: Sum of Interior Angles of a polygon is \(180(n2)\) where \(n\) is the number of sides. So for quadrilateral sum of the angles equals to \(180(42)=360\) degrees. Given: \(\angle{ABC}=110\) and \(\angle{AED}=100\). Question: \(\angle{BCD}\angle{ADE}=?\). Attachment: DS.jpg Now as \(\angle{ABC}=110\) and \(\angle{AED}=100\) and the sum of all angles is 360 degrees then the sum of other two angles in quadrilateral must be \(\angle{BCD}+\angle{BAE}=360(110+100)=150\). (1) \(\angle{DAB}=45\) > \(\angle{BAE}=\angle{DAB}+\angle{DAE}=45+\angle{DAE}\), but \(\angle{DAE}=180100\angle{ADE}=80\angle{ADE}\) (the sum of interior angles in triangle ADE equals to 180 degrees) > \(\angle{BAE}=45+80\angle{ADE}=125\angle{ADE}\). So \(\angle{BCD}+\angle{BAE}=150\) becomes \(\angle{BCD}+125\angle{ADE}=150\) > \(\angle{BCD}\angle{ADE}=25\). Sufficient. (2) \(\angle{BCD}+\angle{ADC}=205\) > \(\angle{ADC}=180\angle{ADE}\) (straight line) > \(\angle{BCD}+180\angle{ADE}=205\) > \(\angle{BCD}\angle{ADE}=25\). Sufficient. Answer: D. OPEN DISCUSSION OF THIS QUESTION IS HERE: thisdsijustcannotfigureoutiamgettinge99063.html== Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
_________________




Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d
[#permalink]
14 Aug 2017, 03:18






