GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 24 May 2019, 14:41

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d

Author Message
Intern
Status: UF BSBA '15 - Preparing for the future
Joined: 09 May 2011
Posts: 24
Location: United States
GPA: 3.87
WE: Human Resources (Consulting)
In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d  [#permalink]

### Show Tags

Updated on: 23 Jun 2011, 20:27
1
00:00

Difficulty:

(N/A)

Question Stats:

71% (00:18) correct 29% (01:08) wrong based on 7 sessions

### HideShow timer Statistics

In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD?

(1) Angle DAB = 45 degrees

(2) Angle ADC + angle BCD = 205 degrees

Hello. I am doing the PR1012, and I came across this question. I got it wrong to begin with, but I also do not understand their brief explanation. Please help me. Just for the record I am in the college class of 2015, but I need to take the GMAT before the end of my sophomore year for a combined degree program (shooting for 700; I know it is really hard!). Eventually I may want an MBA, though. I am studying now to ease into it. I am pretty smart for the most part, but I do badly on tests. I got a 1380 SAT (670M, 710CR) with a little studying. Anyway, here is the question.

After one day of studying I already hate the data questions.

In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD?

1. Angle DAB = 45 degrees

2. Angle ADC + angle BCD = 205 degrees

OPEN DISCUSSION OF THIS QUESTION IS HERE: this-ds-i-just-cannot-figure-out-i-am-getting-e-99063.html

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

Originally posted by jw on 23 Jun 2011, 14:31.
Last edited by jw on 23 Jun 2011, 20:27, edited 1 time in total.
Senior Manager
Joined: 24 Mar 2011
Posts: 341
Location: Texas
Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d  [#permalink]

### Show Tags

23 Jun 2011, 15:10
st-2 is fairly simple to get BCD - ADE, so st is sufficient.

as per st -1, BCD = 360-110-100-45-DAE
BCD = 105-DAE

combining both eqns, BCD = 105-80+ADE
==> BCD - ADE = 25
sufficient.
Intern
Status: UF BSBA '15 - Preparing for the future
Joined: 09 May 2011
Posts: 24
Location: United States
GPA: 3.87
WE: Human Resources (Consulting)
Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d  [#permalink]

### Show Tags

23 Jun 2011, 22:47
My apologies for mis-posting.

Please move this to the data sufficiency forum.
Intern
Joined: 08 Mar 2011
Posts: 9
Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d  [#permalink]

### Show Tags

24 Jun 2011, 13:28
St 2 is very simple, as discussed in the above post. But I solved the first stmt like below, I hope it'll help you!
Let <BCD = y; <ADE = x; therefore <CDA = 180 - x (since, <CDA and <ADE are supplimentary)

Now sum of angles of quadrilateral ABCD is 360;
<DAB + <ABC + <BCD + <CDA = 360 => 45 + 110 + Y + 180 - X = 360

You can get the difference b/t y and X which is the answer for the question. Therefore the answer is D
Intern
Status: UF BSBA '15 - Preparing for the future
Joined: 09 May 2011
Posts: 24
Location: United States
GPA: 3.87
WE: Human Resources (Consulting)
Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d  [#permalink]

### Show Tags

24 Jun 2011, 14:39
I still do not see how statement two is so simple.
Retired Moderator
Joined: 20 Dec 2010
Posts: 1772
Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d  [#permalink]

### Show Tags

24 Jun 2011, 14:50
jw wrote:
I still do not see how statement two is so simple.

Sum of angles in a straight line is 180.

2.

Sufficient.
_________________
Math Expert
Joined: 02 Sep 2009
Posts: 55271
Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d  [#permalink]

### Show Tags

14 Aug 2017, 03:18
jw wrote:

In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD?

(1) Angle DAB = 45 degrees

(2) Angle ADC + angle BCD = 205 degrees

Hello. I am doing the PR1012, and I came across this question. I got it wrong to begin with, but I also do not understand their brief explanation. Please help me. Just for the record I am in the college class of 2015, but I need to take the GMAT before the end of my sophomore year for a combined degree program (shooting for 700; I know it is really hard!). Eventually I may want an MBA, though. I am studying now to ease into it. I am pretty smart for the most part, but I do badly on tests. I got a 1380 SAT (670M, 710CR) with a little studying. Anyway, here is the question.

After one day of studying I already hate the data questions.

In the figure above, if angle ABC = 110 degrees, and angle AED = 100 degrees, then angle ADE is how many degrees smaller than angle BCD?

1. Angle DAB = 45 degrees

2. Angle ADC + angle BCD = 205 degrees

Important property of polygons: Sum of Interior Angles of a polygon is $$180(n-2)$$ where $$n$$ is the number of sides.

So for quadrilateral sum of the angles equals to $$180(4-2)=360$$ degrees.

Given: $$\angle{ABC}=110$$ and $$\angle{AED}=100$$. Question: $$\angle{BCD}-\angle{ADE}=?$$.
Attachment:
DS.jpg
Now as $$\angle{ABC}=110$$ and $$\angle{AED}=100$$ and the sum of all angles is 360 degrees then the sum of other two angles in quadrilateral must be $$\angle{BCD}+\angle{BAE}=360-(110+100)=150$$.

(1) $$\angle{DAB}=45$$ --> $$\angle{BAE}=\angle{DAB}+\angle{DAE}=45+\angle{DAE}$$, but $$\angle{DAE}=180-100-\angle{ADE}=80-\angle{ADE}$$ (the sum of interior angles in triangle ADE equals to 180 degrees) --> $$\angle{BAE}=45+80-\angle{ADE}=125-\angle{ADE}$$. So $$\angle{BCD}+\angle{BAE}=150$$ becomes $$\angle{BCD}+125-\angle{ADE}=150$$ --> $$\angle{BCD}-\angle{ADE}=25$$. Sufficient.

(2) $$\angle{BCD}+\angle{ADC}=205$$ --> $$\angle{ADC}=180-\angle{ADE}$$ (straight line) --> $$\angle{BCD}+180-\angle{ADE}=205$$ --> $$\angle{BCD}-\angle{ADE}=25$$. Sufficient.

OPEN DISCUSSION OF THIS QUESTION IS HERE: this-ds-i-just-cannot-figure-out-i-am-getting-e-99063.html

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________
Re: In the figure above, if angle ABC = 110 degrees, and angle AED = 100 d   [#permalink] 14 Aug 2017, 03:18
Display posts from previous: Sort by