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Math Expert V
Joined: 02 Sep 2009
Posts: 56268
In the figure above, if PQRS is a parallelogram, then y - x =  [#permalink]

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Difficulty:   15% (low)

Question Stats: 85% (01:01) correct 15% (01:29) wrong based on 24 sessions

### HideShow timer Statistics  In the figure above, if PQRS is a parallelogram, then y - x =

A. 15°
B. 30°
C. 80°
D. 115°
E. 210°

Attachment: image042.gif [ 1.22 KiB | Viewed 545 times ]

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VP  D
Status: Learning stage
Joined: 01 Oct 2017
Posts: 1028
WE: Supply Chain Management (Energy and Utilities)
Re: In the figure above, if PQRS is a parallelogram, then y - x =  [#permalink]

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Bunuel wrote: In the figure above, if PQRS is a parallelogram, then y - x =

A. 15°
B. 30°
C. 80°
D. 115°
E. 210°

Attachment:
image042.gif

We have 2y+50=180
Or, 2y=130
Or, y=65
We know, adjacent angles of a parallelogram one supplementary.
So, x+2y=180
Or, x+130=180
Or, x=50

So, y-x=65-50=15

Ans. (A)
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VP  D
Joined: 31 Oct 2013
Posts: 1392
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
Re: In the figure above, if PQRS is a parallelogram, then y - x =  [#permalink]

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Bunuel wrote: In the figure above, if PQRS is a parallelogram, then y - x =

A. 15°
B. 30°
C. 80°
D. 115°
E. 210°

Attachment:
image042.gif

2y + 30 = 180

2y = 130

y = 65.

Sum of all the angles :

2y + 2y +x + x = 360

130 + 130 + 2x = 360

260 + 2x = 360

x = 50.

(y - x ) = 65 - 50 = 15.

Intern  B
Joined: 02 Sep 2015
Posts: 42
Re: In the figure above, if PQRS is a parallelogram, then y - x =  [#permalink]

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2y + 50 = 180
2y = 130
y = 65.

Since it is a parallelogram, X need not be calculated. X = 50 (Please confirm ?)

Y - X = 65 - 50 = 15

Manager  S
Joined: 20 Jul 2018
Posts: 88
GPA: 2.87
Re: In the figure above, if PQRS is a parallelogram, then y - x =  [#permalink]

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2y=180-50
2y=130
y=65

As PS and QR are parallel
So x=50
x-y=65-50=15

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Hasnain Afzal

"When you wanna succeed as bad as you wanna breathe, then you will be successful." -Eric Thomas Re: In the figure above, if PQRS is a parallelogram, then y - x =   [#permalink] 24 Aug 2018, 01:23
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