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In the figure above, P and S are points on the x-axis. What is the ar

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Bunuel
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In the figure above, P and S are points on the x-axis. What is the ar [#permalink] New post   15 Feb 2018, 23:39
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In the figure above, P and S are points on the x-axis. What is the area of square PQRS?

(1) The coordinates of point P are (2, 0).

(2) The coordinates of point R are (6, 4).


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Hatakekakashi
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In the figure above, P and S are points on the x-axis. What is the ar [#permalink] New post   15 Feb 2018, 23:56
Bunuel wrote:

In the figure above, P and S are points on the x-axis. What is the area of square PQRS?

(1) The coordinates of point P are (2, 0).

(2) The coordinates of point R are (6, 4).


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Attachment:
2018-02-16_1038.png



We know a square has equal sides

statement 1 P(2,0)

doesn't help in knowing the length of the side of the given square
insufficient

statement 2 R(6.4)

we know SR = B

sufficient

(B) imo
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Re: In the figure above, P and S are points on the x-axis. What is the ar [#permalink] New post   16 Feb 2018, 00:09
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Hatakekakashi wrote:
Bunuel wrote:

In the figure above, P and S are points on the x-axis. What is the area of square PQRS?

(1) The coordinates of point P are (2, 0).

(2) The coordinates of point R are (6, 4).


Show Spoiler
Attachment:
2018-02-16_1038.png



We know a square has equal sides

statement 1 P(2,0)

doesn't help in knowing the length of the side of the given square
insufficient

statement 2 R(6.4)

if we knew another diagonal we can find the length of diagonal and since it's not given
insufficient

combining

we have coordinates of 2 diagonals and the distance b/w them gives length of the diagonal and thus we can find the side and then area

(C) imo



Shouldnt , B be sufficient,

Since R has co ordinates (6,4) which essentially means the vertical distance SR is 4 units , since the figure is square we can thus find the area !!

pls suggest if m making a mistake
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Re: In the figure above, P and S are points on the x-axis. What is the ar [#permalink] New post   16 Feb 2018, 00:16
doomedcat wrote:


Shouldnt , B be sufficient,

Since R has co ordinates (6,4) which essentially means the vertical distance SR is 4 units , since the figure is square we can thus find the area !!

pls suggest if m making a mistake



That gives OS distance but we don't know PS distance, which is the side of the square

hope this helps
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Re: In the figure above, P and S are points on the x-axis. What is the ar [#permalink] New post   16 Feb 2018, 00:37
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Hatakekakashi wrote:
doomedcat wrote:


Shouldnt , B be sufficient,

Since R has co ordinates (6,4) which essentially means the vertical distance SR is 4 units , since the figure is square we can thus find the area !!

pls suggest if m making a mistake



That gives OS distance but we don't know PS distance, which is the side of the square

hope this helps


Hi

From second statement we get that OS distance is 6, but we also get that SR distance is 4, and since its a square with each side equal we now know that PS is also 4.
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Re: In the figure above, P and S are points on the x-axis. What is the ar [#permalink] New post   16 Feb 2018, 00:46
amanvermagmat wrote:
Hatakekakashi wrote:
doomedcat wrote:


Shouldnt , B be sufficient,

Since R has co ordinates (6,4) which essentially means the vertical distance SR is 4 units , since the figure is square we can thus find the area !!

pls suggest if m making a mistake



That gives OS distance but we don't know PS distance, which is the side of the square

hope this helps


Hi

From second statement we get that OS distance is 6, but we also get that SR distance is 4, and since its a square with each side equal we now know that PS is also 4.


how foolish to make a silly mistake.. thanks made the edit :D

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Re: In the figure above, P and S are points on the x-axis. What is the ar [#permalink]
16 Feb 2018, 00:46
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Bunuel
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