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# In the figure above, RS = ST, and the coordinates of S are (k,3). What

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Joined: 02 Sep 2009
Posts: 58335
In the figure above, RS = ST, and the coordinates of S are (k,3). What  [#permalink]

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15 Dec 2017, 02:15
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In the figure above, RS = ST, and the coordinates of S are (k,3). What is the value of k?

(A) –3
(B) √3
(C) 0
(D) √3
(E) 3

Attachment:

2017-12-15_1300_001.png [ 5.26 KiB | Viewed 1101 times ]

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Re: In the figure above, RS = ST, and the coordinates of S are (k,3). What  [#permalink]

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06 Jan 2018, 10:21
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How the answer could be E? Since S is in II Quadrant so x coordinate must be negative. I think it should be A.
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Re: In the figure above, RS = ST, and the coordinates of S are (k,3). What  [#permalink]

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06 Jan 2018, 10:24
Mehemmed wrote:
How the answer could be E? Since S is in II Quadrant so x coordinate must be negative. I think it should be A.

Yes, the correct answer is A, not E.
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In the figure above, RS = ST, and the coordinates of S are (k,3). What  [#permalink]

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06 Jan 2018, 14:39
Bunuel wrote:

In the figure above, RS = ST, and the coordinates of S are (k,3). What is the value of k?

(A) –3
(B) √3
(C) 0
(D) √3
(E) 3

Attachment:
2017-12-15_1300_001.png

Vertex S is in Quadrant II, where x is negative and y is positive.

S coordinates: (k, 3)
$$k$$ is the x-coordinate.
$$k$$ (x-coordinate) must be negative.

Only one choice meets that condition: Answer A.
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In the figure above, RS = ST, and the coordinates of S are (k,3). What   [#permalink] 06 Jan 2018, 14:39
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# In the figure above, RS = ST, and the coordinates of S are (k,3). What

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