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21 Jul 2016, 07:55
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Bunuel
guireif
Hi guys,
I know this is an old question, but I'm not sure about one thing.
Should I assume by looking at the figure that CE=RB? Because in the first statement it just say that RE is less than twice the length of BR, but how do I know that the triangle is "centered" with the square, by not looking the second statement?
thanks
I know this is an old question, but I'm not sure about one thing.
Should I assume by looking at the figure that CE=RB? Because in the first statement it just say that RE is less than twice the length of BR, but how do I know that the triangle is "centered" with the square, by not looking the second statement?
thanks
Since AB = AC (triangle ABC is isosceles), and AS = AQ, then CE must be equal to RB.
Now I got it. Haven't noticed that AS=AQ. Perfect. Thank you so much
22 Jul 2016, 08:35
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AccipiterQ
Attachment:
The attachment 2967-1.gif is no longer available
In the figure above, SQRE is a square, AB = AC, and AS = AQ. What is the difference between the perimeter of triangle ABC and the perimeter of square SQRE?(1) The length of RE is 4 times the length of BR.
(2) The area of triangle ABC is 75% of the area of square SQRE.
2(BR+CE)=RE (since AC=AB && AS=AQ)
CB=RE/2+RE=3/2RE
Take triangle ACD
AC^2(3/4RE)^2+RE^2 (CD=1/2CB &&CB=3/2RE)
AC^2=25/16RE^2
AC=5/4RE
PERIMETER OF ABC=5/4RE+5/4RE+3/2RE=4RE
PERIMETER OF SQ.=4RE
Perimeters are equal.
suff.
(2) 1/2 CB*AD=3/4 RE^2 (75%=3/4)
as AD=RE
CB=3/2RE
same info as (1)
suff.
Ans D
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2967-1.gif [ 2.88 KiB | Viewed 2016 times ]
20 Nov 2020, 21:23
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technically doesn't statement one being sufficient require that point A be centered? And we aren't given the A evenly splits SQ or the BR = CE.
I'm pretty sure i've seen a similar question in which the statement was NOT SUFFICIENT for this very reason.
I'm pretty sure i've seen a similar question in which the statement was NOT SUFFICIENT for this very reason.
