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24 May 2020, 08:38
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
65% (01:31) correct
35%
(01:24)
wrong
based on 282
sessions
History
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Not Attempted Yet
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(1) Points P, Q, and R are midpoints of the edges of the larger rectangular solid.
(2) Both rectangular solids are cubes.
24 May 2020, 08:47
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jkbk1732
If the sides are l, b and h, the bigger rectangular solid has surface area = \(2(lb+bh+lh)\).
We do not know the side or relative measure of the sides of smaller one.
(1) Points P, Q, and R are midpoints of the edges of the larger rectangular solid.
We can straightway see that such 3 sides of 8 smaller ones will form the bigger one, so 1/4.
Otherwise the sides of smaller solid are l/2, b/2, h/2, so surface area = \(2(\frac{lb}{4}+\frac{bh}{4}+\frac{lh}{4})=\frac{(lb+bh+lh)}{2} = \frac{2(lb+bh+hl)}{4}\)
Ratio =\(\frac{1}{4}\)
Suff
(2) Both rectangular solids are cubes
But we do not know the ratio of sides of both the solids.
Insuff
A
12 Aug 2022, 09:14
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