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In the figure above, what is the area of the square inscribed in the

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In the figure above, what is the area of the square inscribed in the [#permalink]

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New post 23 Nov 2017, 22:17
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In the figure above, what is the area of the square inscribed in the circle of radius a?

(A) 2a
(B) √2*a^2
(C) a^2
(D) 2a^2
(E) 4a^2

[Reveal] Spoiler:
Attachment:
2017-11-23_2025.png
2017-11-23_2025.png [ 5.3 KiB | Viewed 278 times ]
[Reveal] Spoiler: OA

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In the figure above, what is the area of the square inscribed in the [#permalink]

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New post 24 Nov 2017, 05:32
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The diameter of the circle is the diagonal of the square
Since the radius of the circle is a, the diameter will be 2a
Side√2 = 2a

The side of the square is \(\frac{(√2*√2a)}{√2} = √2*a\)

Therefore, the area of the square with side(\(√2*a\)) is \(2a^2\)(Option D)
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Re: In the figure above, what is the area of the square inscribed in the [#permalink]

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New post 24 Nov 2017, 07:45
In the figure above, what is the area of the square inscribed in the circle of radius a?

(A) 2a
(B) √2*a^2
(C) a^2
(D) 2a^2
(E) 4a^2

1) Let x be a side of the square
2) diametr AC is equal to 2a
3) In the right triangle ABC:
\(x^2 + x^2 = (2a)^2\)
\(2x^2 = 4a^2\)
\(x^2 = 2a^2\)

x^2 is equal to area of the square ABCD so that is 2a^2 ; the answer is D
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Re: In the figure above, what is the area of the square inscribed in the   [#permalink] 24 Nov 2017, 07:45
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