Bunuel wrote:

In the figure below, what is the perimeter of triangle BCD?

(A) 4 + 4√3

(B) 12

(C) 12 + 4√3

(D) 8 + 8√3

(E) 16√2

Attachment:

2018-10-04_1334.png

We can use the Pythagorean theorem to determine the length of side BD:

4^2 + (4√2)^2 = BD^2

16 + 32 = BD^2

48 = BD^2

√48 = BD

Using the Pythagorean theorem we can determine side CD.

4^2 + (√48)^2 = CD^2

16 + 48 = CD^2

64 = CD^2

8 = CD

So the perimeter of triangle BCD is 4 + 8 + √48 = 12 + 4√3

Answer: C

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Founder and CEO

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