JanarthCj wrote:
roysaurabhkr wrote:
Answer is B
Quick trick: Side opposite to the biggest angle in a triangle is biggest. (And Side opposite to the smallest angle in a triangle is smallest)
In Triangle ACD:
Statement A
x= 50 degree. Thus, angle ACD = 50 degree. No conclusion can be drawn about the other angles and hence the relative size of the sides.
Statement B angle Z = 70 degree.
The sum of remaining angles in the triangle = 110 degree.
Thus one of the remaining two angles is definitely < 70 degree.
Thus, angle z is not the smallest angle
Thus we know for sure that the side opposite to angle Z is not the smallest.
Hence answer B.
It is possible that the other two angles could be 100 & 10, 90 & 20 or 80 & 30.
Can you please explain how you eliminated the above-mentioned possibilities?
Best,
Cj
Hi Cj,
The side opposite the smallest angle in a triangle will be the smallest side.
ST1: we know CAD=50, so ACD+ADC=130. If ADC<50, then it will be the smallest angle and thus, the side opposite to it will be the smallest.
If ADC > 50, then AC won't be the smallest. We can't determine ADC for sure, so not sufficient.
ST2: z=70 => CAD+ACD = 110. If CAD=ACD, then each angle equals to 55. If, they are not equal then for an increment of 1 in one angle, the other angle will decrease by 1, since their sum is constant. So, for sure one of the angles will be < 56. This means that z is not the smallest angle. Thus, AC is not the smallest side.
Sufficient.