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In the figure to the right, the equation of the line is y = 9x/10 + k

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In the figure to the right, the equation of the line is y = 9x/10 + k  [#permalink]

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New post 09 Apr 2019, 03:20
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

76% (01:45) correct 24% (02:05) wrong based on 34 sessions

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In the figure to the right, the equation of the line is y = 9x/10 + k . Which one of the following must be true about line segments AO and BO ?

(A) AO > BO
(B) AO < BO
(C) AO ≤ BO
(D) AO = BO
(E) AO = BO/2

Source: Nova GMAT
Difficulty Level: 600

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Re: In the figure to the right, the equation of the line is y = 9x/10 + k  [#permalink]

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New post 09 Apr 2019, 03:50
To get the length of BO, Substitute x=0 in equation y = 9x/10 + k, We get y=k . Hence BO= k

To get the length of AO, Substitute y=0 in th equation above and you get x= -10k/9 (Distance (AO= 10k/9)) (As distance can never be a negative quantity)

Clearly from above two values we know AO>BO

Correct Answer is A
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Re: In the figure to the right, the equation of the line is y = 9x/10 + k  [#permalink]

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New post 14 Apr 2019, 01:18
no need to find exact values, i think

M is the rate of change in y, for a change in x

since m is 9/10... for every 10 unit increase in x, y increases by 9... so OB (height of the triangle) will be shorter than OA (base)

hence A
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Re: In the figure to the right, the equation of the line is y = 9x/10 + k   [#permalink] 14 Apr 2019, 01:18
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In the figure to the right, the equation of the line is y = 9x/10 + k

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