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m1033512
IMO D

triangle ABC and EDC are congruent

so the ratio of corresponding sides will be equal .

we get AC = 27

area = 1/2*27*9 = 121.5


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How did you get AC = 27? More explanation needed.
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from Ec/CD = 3 and EC = 12
we get CD = 4

now in similar triangle abc and edc

EC/AC= CD/BC


put the values, you will get AC = 27


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tanx=EC/CD=AC/BC
3=AC/9
OR AC=27
Area of ABC=0.5*27*9=121.5
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m1033512
from Ec/CD = 3 and EC = 12
we get CD = 4

now in similar triangle abc and edc

EC/AC= CD/BC

put the values, you will get AC = 27
Posted from my mobile device
How are abc and edc similar?
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Hello from the GMAT Club BumpBot!

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