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# In the formula w=p / (v)^1/t integers p and t are positive

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Intern
Joined: 11 Jul 2011
Posts: 19

Kudos [?]: 11 [0], given: 6

Location: India
Concentration: Entrepreneurship, Marketing
GMAT Date: 03-08-2013
WE: Manufacturing and Production (Manufacturing)
In the formula w=p / (v)^1/t integers p and t are positive [#permalink]

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11 Oct 2012, 09:29
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (01:45) wrong based on 2 sessions

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In the formula w=p / (v)^1/t integers p and t are positive constants. If w =2 when v = 1 and if w=1/2 when v = 64, then t =
(A) 1
(B) 2
(C) 3
(D) 4
(E) 16
[Reveal] Spoiler: OA

Last edited by abhishek1990p on 14 Oct 2012, 11:08, edited 2 times in total.

Kudos [?]: 11 [0], given: 6

Director
Status: Tutor - BrushMyQuant
Joined: 05 Apr 2011
Posts: 622

Kudos [?]: 763 [0], given: 59

Location: India
Concentration: Finance, Marketing
Schools: XLRI (A)
GMAT 1: 700 Q51 V31
GPA: 3
WE: Information Technology (Computer Software)

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14 Oct 2012, 09:11
If w =2 when v = 1 and if w=? when v = 64

I think the question is incomplete
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How to Solve :
Statistics || Reflection of a line || Remainder Problems || Inequalities

Kudos [?]: 763 [0], given: 59

Manager
Joined: 29 Apr 2012
Posts: 101

Kudos [?]: 80 [0], given: 47

Location: United States
GMAT Date: 10-22-2012

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14 Oct 2012, 09:27
abhishek1990p wrote:
In the formula w=p / (t√v) integers p and t are positive constants. If w =2 when v = 1 and if when v = 64, then t =
(A) 1
(B) 2
(C) 3
(D) 4
(E) 16

hey i dont understand if its (v)^1/t OR t*[(v)^1/2]
can you please be specific...coz i am getting two variable here.
What is the source?

Kudos [?]: 80 [0], given: 47

Intern
Joined: 10 Mar 2014
Posts: 19

Kudos [?]: 6 [0], given: 14

Location: United States
Concentration: General Management, Finance
GMAT 1: 680 Q46 V38
GPA: 3
WE: Programming (Computer Software)
Re: In the formula w=p / (v)^1/t integers p and t are positive [#permalink]

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15 Jul 2014, 23:07

Substituting from statement 1:
2=p/(1)^(1/t) -{1}

Substituting from statement 2:
1/2=p/(64)^(1/t) -{2}

{1}/{2} gives:
2/(1/2)=[p/(1)^(1/t)]/[p/(64)^(1/t)]

Simplifying:
4=(64)^1/t
or 4^t=64

Choice C

Kudos [?]: 6 [0], given: 14

Re: In the formula w=p / (v)^1/t integers p and t are positive   [#permalink] 15 Jul 2014, 23:07
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