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In the rectangular coordinate system above, for which of the shaded re

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monirjewel
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In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  Updated on: 08 Oct 2019, 03:46
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In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

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Originally posted by monirjewel on 22 Nov 2010, 06:29.
Last edited by Bunuel on 08 Oct 2019, 03:46, edited 2 times in total.
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Bunuel
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  22 Nov 2010, 07:56
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In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

The area of a rectangle equals to \(area=width*length\);

The area of a triangle equals to \(area=\frac{1}{2}*base*height\) (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
\(area_P=\frac{1}{2}*4*1=2\);
\(area_Q=1*2=2\);
\(area_R=\frac{2^2}{2}=2\);
\(area_S=\frac{1}{2}*3*1=1.5\).

Answer: D.
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  20 Oct 2011, 22:26
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Area of a triangle = 1/2 * Base * Height,
from the graph we can find out length of base and height of the triangles and rectangles.
P: Base = 4 Height = 1 Area = 1/2 (4)(1) = 2
Q: Base = 1 Height = 2 Area = Base * Height = 1 * 2 = 2
R: For a rhombus area can be calculated using the value of the diagonals ( D1 * D2 ) / 2
i:e (2*2)/2 = 2
S: Base = 3 Height = 1 Area = 1/2 (3)(1) = 1.5

So answer is D :)
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In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  06 Mar 2014, 02:34
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Bumping for review and further discussion.

GEOMETRY: Shaded Region Problems!
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  04 May 2014, 03:05
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to \(area=width*length\);

The area of a triangle equals to \(area=\frac{1}{2}*base*height\) (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
\(area_P=\frac{1}{2}*4*1=2\);
\(area_Q=1*2=2\);
\(area_R=\frac{2^2}{2}=2\);
\(area_S=\frac{1}{2}*3*1=1.5\).

Answer: D.





Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  04 May 2014, 03:14
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b2bt wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to \(area=width*length\);

The area of a triangle equals to \(area=\frac{1}{2}*base*height\) (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
\(area_P=\frac{1}{2}*4*1=2\);
\(area_Q=1*2=2\);
\(area_R=\frac{2^2}{2}=2\);
\(area_S=\frac{1}{2}*3*1=1.5\).

Answer: D.





Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D


Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. \(area_{square}=\frac{d^2}{2}\) and \(area_{rhombus}=\frac{d_1*d_2}{2}\).
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  21 Jul 2014, 10:54
Bunuel wrote:
b2bt wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to \(area=width*length\);

The area of a triangle equals to \(area=\frac{1}{2}*base*height\) (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
\(area_P=\frac{1}{2}*4*1=2\);
\(area_Q=1*2=2\);
\(area_R=\frac{2^2}{2}=2\);
\(area_S=\frac{1}{2}*3*1=1.5\).

Answer: D.





Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D


Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. \(area_{square}=\frac{d^2}{2}\) and \(area_{rhombus}=\frac{d_1*d_2}{2}\).


Bunuel for calculating area of R : how did you get 2^2 /2 , where is 2 coming from? Can you explain the counting of boxes?

same question for S and Q
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  21 Jul 2014, 11:30
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sagnik2422 wrote:
Bunuel wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to \(area=width*length\);

The area of a triangle equals to \(area=\frac{1}{2}*base*height\) (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
\(area_P=\frac{1}{2}*4*1=2\);
\(area_Q=1*2=2\);
\(area_R=\frac{2^2}{2}=2\);
\(area_S=\frac{1}{2}*3*1=1.5\).

Answer: D.




Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. \(area_{square}=\frac{d^2}{2}\) and \(area_{rhombus}=\frac{d_1*d_2}{2}\).


Bunuel for calculating area of R : how did you get 2^2 /2 , where is 2 coming from? Can you explain the counting of boxes?

same question for S and Q



R is a square --> the area of a square=diagonal^2/2 --> diagonal of R = 2 --> area = 2^2/2.

Q is a rectangle --> the area = length*width = 1*2.

S is a triangle --> the area = 1/2*base*height = 1/2*3*1 (consider vertical side as base).

Hope it's clear.
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  21 Jul 2014, 13:07
Great explanation, but how can I see that diagonal of R is 2? (like can you possibly label this on the diagram or give coordinates) also, I don't see how the width is 2 for the rectangle.

Sorry for the bother.
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  24 Jan 2017, 07:35
monirjewel wrote:
Attachment:
Untitled.png
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

Show Spoiler
Attachment:
Clips.jpg


Hi,

By using logic, Calculate the area of P=(1/2)bh=>(1/2)(4)(1)=>2

Now see the options and quickly eliminate A,B,C (doesn't contain P)

Now calculate Are of S=(1/2)(3)(1) is not equal to 2 hence eliminate E

Ans:D
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  25 Jun 2019, 01:57
R is a square --> the area of a square=diagonal^2/2 --> diagonal of R = 2 --> area = 2^2/2.

About this, how did u figure that 2 is a diagonal and not a side length of square?
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  19 Jul 2019, 19:00
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People can be confused over R.

Use a right triangle to articulate side length of square R as per my diagram.
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  12 Mar 2020, 06:56
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monirjewel wrote:

In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

Show Spoiler
Attachment:
Untitled.png

Attachment:
Clips.jpg



Observe that the area of each small square formed by the gridlines is 1.

The area of region P is 2 since P is a triangle with base = 4 and height = 1. Thus, the area of P is (1/2)(4)(1) = 2.

The area of region Q is 2 since Q is a rectangle with length = 2 and width = 1. Thus, the area of Q is (2)(1) = 2.

The area of region R is 2 since R can be broken into four right triangles, each of which has an area of exactly 1/2.

The area of region S, however, is not 2. We can see that S is a triangle with base = 3 and height = 1. Thus, the area of S is (1/2)(3)(1) = 3/2.

Answer: D
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  30 Oct 2021, 03:38
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Bunuel wrote:
Bumping for review and further discussion.

GEOMETRY: Shaded Region Problems!



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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  30 Oct 2021, 03:42
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TBT wrote:
Bunuel wrote:
Bumping for review and further discussion.

GEOMETRY: Shaded Region Problems!



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Fixed the lin. Thank you!

Here it is again: GEOMETRY: Shaded Region Problems!
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Re: In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  17 Nov 2022, 10:45
Bunuel
For R, would it be incorrect to just split it into two triangles? I did for one triangle 1/2*b*h=1/2*2*1 --> *2 triangles = area of 2
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In the rectangular coordinate system above, for which of the shaded re [#permalink] New post  17 Nov 2022, 10:50
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woohoo921 wrote:
Bunuel
For R, would it be incorrect to just split it into two triangles? I did for one triangle 1/2*b*h=1/2*2*1 --> *2 triangles = area of 2

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