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Manager  Joined: 06 Feb 2010
Posts: 137
Schools: University of Dhaka - Class of 2010
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In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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2
21 00:00

Difficulty:   5% (low)

Question Stats: 81% (01:15) correct 19% (01:11) wrong based on 640 sessions

### HideShow timer Statistics In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

Attachment: Untitled.png [ 19.84 KiB | Viewed 21004 times ]

Attachment: Clips.jpg [ 34.76 KiB | Viewed 24939 times ]

Originally posted by monirjewel on 22 Nov 2010, 05:29.
Last edited by Bunuel on 08 Oct 2019, 02:46, edited 2 times in total.
Edited the question
Math Expert V
Joined: 02 Sep 2009
Posts: 64068
Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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1
4 In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

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Manager  Joined: 12 Jul 2011
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Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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1
1
2
Area of a triangle = 1/2 * Base * Height,
from the graph we can find out length of base and height of the triangles and rectangles.
P: Base = 4 Height = 1 Area = 1/2 (4)(1) = 2
Q: Base = 1 Height = 2 Area = Base * Height = 1 * 2 = 2
R: For a rhombus area can be calculated using the value of the diagonals ( D1 * D2 ) / 2
i:e (2*2)/2 = 2
S: Base = 3 Height = 1 Area = 1/2 (3)(1) = 1.5

So answer is D Math Expert V
Joined: 02 Sep 2009
Posts: 64068
Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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Bumping for review and further discussion.

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Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D
Math Expert V
Joined: 02 Sep 2009
Posts: 64068
Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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2
2
b2bt wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D

Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. $$area_{square}=\frac{d^2}{2}$$ and $$area_{rhombus}=\frac{d_1*d_2}{2}$$.
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Posts: 31
Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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Bunuel wrote:
b2bt wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D

Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. $$area_{square}=\frac{d^2}{2}$$ and $$area_{rhombus}=\frac{d_1*d_2}{2}$$.

Bunuel for calculating area of R : how did you get 2^2 /2 , where is 2 coming from? Can you explain the counting of boxes?

same question for S and Q
Math Expert V
Joined: 02 Sep 2009
Posts: 64068
Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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sagnik2422 wrote:
Bunuel wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. $$area_{square}=\frac{d^2}{2}$$ and $$area_{rhombus}=\frac{d_1*d_2}{2}$$.

Bunuel for calculating area of R : how did you get 2^2 /2 , where is 2 coming from? Can you explain the counting of boxes?

same question for S and Q R is a square --> the area of a square=diagonal^2/2 --> diagonal of R = 2 --> area = 2^2/2.

Q is a rectangle --> the area = length*width = 1*2.

S is a triangle --> the area = 1/2*base*height = 1/2*3*1 (consider vertical side as base).

Hope it's clear.
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Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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Great explanation, but how can I see that diagonal of R is 2? (like can you possibly label this on the diagram or give coordinates) also, I don't see how the width is 2 for the rectangle.

Sorry for the bother.
Intern  Joined: 20 May 2014
Posts: 31
Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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also how is the height 1 for S?
Math Expert V
Joined: 02 Sep 2009
Posts: 64068
Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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sagnik2422 wrote:
Great explanation, but how can I see that diagonal of R is 2? (like can you possibly label this on the diagram or give coordinates) also, I don't see how the width is 2 for the rectangle.

Sorry for the bother.

Ask yourself how many units are there in the diagonal of R, in the width of the rectangle, ...

Sorry, I don't know how to explain it better.
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Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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monirjewel wrote:
Attachment:
Untitled.png
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

Attachment:
Clips.jpg

Hi,

By using logic, Calculate the area of P=(1/2)bh=>(1/2)(4)(1)=>2

Now see the options and quickly eliminate A,B,C (doesn't contain P)

Now calculate Are of S=(1/2)(3)(1) is not equal to 2 hence eliminate E

Ans:D
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Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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R is a square --> the area of a square=diagonal^2/2 --> diagonal of R = 2 --> area = 2^2/2.

About this, how did u figure that 2 is a diagonal and not a side length of square?
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Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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2
People can be confused over R.

Use a right triangle to articulate side length of square R as per my diagram.
Attachments Capture.JPG [ 47.76 KiB | Viewed 3424 times ]

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Re: In the rectangular coordinate system above, for which of the shaded re  [#permalink]

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monirjewel wrote: In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

Attachment:
Untitled.png

Attachment:
Clips.jpg

Observe that the area of each small square formed by the gridlines is 1.

The area of region P is 2 since P is a triangle with base = 4 and height = 1. Thus, the area of P is (1/2)(4)(1) = 2.

The area of region Q is 2 since Q is a rectangle with length = 2 and width = 1. Thus, the area of Q is (2)(1) = 2.

The area of region R is 2 since R can be broken into four right triangles, each of which has an area of exactly 1/2.

The area of region S, however, is not 2. We can see that S is a triangle with base = 3 and height = 1. Thus, the area of S is (1/2)(3)(1) = 3/2.

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If you find one of my posts helpful, please take a moment to click on the "Kudos" button. Re: In the rectangular coordinate system above, for which of the shaded re   [#permalink] 12 Mar 2020, 05:56

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