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In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa

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In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 06 Oct 2016, 04:17
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In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equal area, what are the coordinates of point R ?

(1)The coordinates of point P are (0,12).
(2) OP = OQ and QS = RS.

Attachment:
2016-10-06_1616.png
2016-10-06_1616.png [ 13.34 KiB | Viewed 3566 times ]

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Re: In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 06 Oct 2016, 06:56
3
ΔOPQ and ΔQRS have equal area --> 0.5*OP*OQ = 0.5*QS*RS

St1: The coordinates of point P are (0,12) --> OP = 12
12*OQ = QS*RS
Clearly insufficient as we do not know the lengths of OQ, QS and RS.

St2: OP = OQ and QS = RS --> Not Sufficient as we do not know the values of the given lengths

Combining St1 and St2: OP^2 = QS^2 --> OP = QS
Hence OP = OQ = QS = RS = 12
Co-ordinates of R = (24,12)
Sufficient

Answer: C
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Re: In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 06 Oct 2016, 07:04
Vyshak wrote:
ΔOPQ and ΔQRS have equal area --> 0.5*OP*OQ = 0.5*QS*RS

St1: The coordinates of point P are (0,12) --> OP = 12
12*OQ = QS*RS
Clearly insufficient as we do not know the lengths of OQ, QS and RS.

St2: OP = OQ and QS = RS --> Not Sufficient as we do not know the values of the given lengths

Combining St1 and St2: OP^2 = QS^2 --> OP = QS
Hence OP = OQ = QS = RS = 12
Co-ordinates of R = (24,12)
Sufficient

Answer: C


Agree with Vyshak's explanation. Answer must be C.
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Re: In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 06 Oct 2016, 07:30
Bunuel wrote:
Image
In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equal area, what are the coordinates of point R ?

(1)The coordinates of point P are (0,12).
(2) OP = OQ and QS = RS.

Attachment:
2016-10-06_1616.png


Statement 1 gives only y co-ordinate value. Without knowing the distance OS we cannot find the co-ordinate of point R.
In Suff..

Statement 2 says both the triangles are isosceles but this data is not suff to find the co-ordinates.
In Suff

Combining we have x co-ordinate of R as 24 and y co-ordinate of R as 12
R (24,12)
Hence C
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Re: In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 09 Jul 2017, 21:34
Bunuel wrote:
Image
In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equal area, what are the coordinates of point R ?

(1)The coordinates of point P are (0,12).
(2) OP = OQ and QS = RS.

Attachment:
2016-10-06_1616.png


Hi I request you to please solve this question. Given below the solution, I couldn't get how op^2 = QS^2
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Re: In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 09 Jul 2017, 22:29
rajatbanik wrote:
Bunuel wrote:
Image
In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equal area, what are the coordinates of point R ?

(1)The coordinates of point P are (0,12).
(2) OP = OQ and QS = RS.

Attachment:
2016-10-06_1616.png


Hi I request you to please solve this question. Given below the solution, I couldn't get how op^2 = QS^2


Image
In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equal area, what are the coordinates of point R ?

Since ΔOPQ and ΔQRS have equal area, then \(\frac{1}{2}*OP*OQ = \frac{1}{2}*RS*QS\), which gives \(OP*OQ = RS*QS\).

(1) The coordinates of point P are (0,12). This implies that OP = 12. Not sufficient.

(2) OP = OQ and QS = RS. No values are given, so this statement is clearly insufficient. But from this statement we get that \(OP^2 = RS^2\) (from \(OP*OQ = RS*QS\)), which gives OP = RS. So, OP = OQ = QS = RS. Basically we get that ΔOPQ and ΔQRS are congruent, similar triangles.

(1)+(2) \(OP^2 = RS^2=12^2\). So, \(OP = OQ = QS = RS=12\). Thus the coordinates of R are (24, 12). Sufficient.

Answer: C.
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Re: In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 15 Jul 2017, 03:50
For statement 1, can't a pythagorean triplet apply? That way A is also sufficient. (12,13,5)
B) is sufficient on its own too, giving us triangle 1 with (0,0) (0,12) and since two sides are equal, (12,0)for the coordinate Q.
And since we have (12,0) we get 24,0 and the last coordinate of R

Could someone explain why D is wrong? And what is the error in the above logic?
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In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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New post 09 Aug 2017, 22:08
\sqrt{}
Madhavi1990 wrote:
For statement 1, can't a pythagorean triplet apply? That way A is also sufficient. (12,13,5)
B) is sufficient on its own too, giving us triangle 1 with (0,0) (0,12) and since two sides are equal, (12,0)for the coordinate Q.
And since we have (12,0) we get 24,0 and the last coordinate of R

Could someone explain why D is wrong? And what is the error in the above logic?


For (1) infinitely many other cases are possible. For example, (12, 1, \(\sqrt{145}\)), (12, 2, \(\sqrt{148}\)), (12, 1.5, \(\sqrt{146.25}\)), ... Generally knowing only one side of a triangle is not enough to find other sides.

For (2) no values are given. You cannot use info from one statement when solving another.
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Re: In the rectangular coordinate system above, if ΔOPQ and ΔQRS have equa  [#permalink]

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