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In the rectangular solid above, AD = 4, BC = 6 and DC = BC/2. What is

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Math Expert
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Joined: 02 Sep 2009
Posts: 59561
In the rectangular solid above, AD = 4, BC = 6 and DC = BC/2. What is  [#permalink]

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New post 04 Dec 2017, 03:41
00:00
A
B
C
D
E

Difficulty:

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Question Stats:

98% (00:40) correct 3% (00:16) wrong based on 57 sessions

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In the rectangular solid above, AD = 4, BC = 6 and DC = BC/2. What is the volume of the solid?

(A) 36
(B) 48
(C) 72
(D) 96
(E) 144

Attachment:
2017-12-04_1435.png
2017-12-04_1435.png [ 4.85 KiB | Viewed 736 times ]
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Re: In the rectangular solid above, AD = 4, BC = 6 and DC = BC/2. What is  [#permalink]

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New post 04 Dec 2017, 04:36
It is a cuboid with
L=AD=4
B=DC=3
H=BC=6

Volume of cuboid = l*b*h
=4*3*6
=72

Imo C


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Re: In the rectangular solid above, AD = 4, BC = 6 and DC = BC/2. What is  [#permalink]

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New post 12 Jan 2018, 07:16
Bunuel wrote:
Image
In the rectangular solid above, AD = 4, BC = 6 and DC = BC/2. What is the volume of the solid?

(A) 36
(B) 48
(C) 72
(D) 96
(E) 144

Attachment:
2017-12-04_1435.png


We are given that AD = 4 = L, BC = 6 = H and DC = BC/2 = 6/2 = 3 = W. Since the volume of a rectangular solid is V = L x W x H, the volume of the solid is V = 4 x 3 x 6 = 72.

Answer: C
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Re: In the rectangular solid above, AD = 4, BC = 6 and DC = BC/2. What is   [#permalink] 12 Jan 2018, 07:16
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