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# In the sequence 1, 2, 4, 8, 16, 32, , each term after the

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In the sequence 1, 2, 4, 8, 16, 32, , each term after the [#permalink]

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25 Apr 2006, 12:34
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In the sequence 1, 2, 4, 8, 16, 32, â€¦, each term after the first is twice the previous term. What is the sum of the 16th, 17th, and 18th terms in the sequence?

A. 2^18
B. 3(2^17)
C. 7(2^16)
D. 3(2^16)
E. 7(2^15)

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Joined: 25 Apr 2006
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25 Apr 2006, 13:27
This series can be written as
1, 2^1,2^2,2^3...
So the nth term = 2^n-1

So the sum of 16,17,18 th term = 2^15 +2^16 + 2^17

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25 Apr 2006, 13:27
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