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16 Aug 2010, 22:20
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C
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In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the "sport" formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the "sport" formulation contains 3 ounces of corn syrup, how many ounces of water does it contain?
a.15
b.30
c.45
d.60
e.90
a.15
b.30
c.45
d.60
e.90
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16 Aug 2010, 22:28
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Standard:
Fl: Corn S: Water = 1:12:30
Sport:
Fl: Corn S: Water = 3:12:180
This simplifies to 1:4:60
If the large bottle has a capacity of x ounces, then
4x / 65 = 3.
So, x = 195 / 4 ounces.
Water = (60 / 65) * (195 / 4) = 60 * 3 / 4 = 45 ounces.
Tricky issues:
How do we figure out 180 in the 2nd line of the equation? It has to be such a number (say p) so that 3 / p will equal 1 / 60. Stems from the question statement that 'the ratio of flavoring to water is half that of the standard formulation'.
Hope this helps. Thanks.
Fl: Corn S: Water = 1:12:30
Sport:
Fl: Corn S: Water = 3:12:180
This simplifies to 1:4:60
If the large bottle has a capacity of x ounces, then
4x / 65 = 3.
So, x = 195 / 4 ounces.
Water = (60 / 65) * (195 / 4) = 60 * 3 / 4 = 45 ounces.
Tricky issues:
How do we figure out 180 in the 2nd line of the equation? It has to be such a number (say p) so that 3 / p will equal 1 / 60. Stems from the question statement that 'the ratio of flavoring to water is half that of the standard formulation'.
Hope this helps. Thanks.
17 Aug 2010, 18:31
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aiming4mba
Standard Formulation:
Flavoring: Corn Syrup : Water
1 : 12: 30
Given ratio b/w Flavoring and Corn Syrup is thrice the standard formulation -
\(3 * (1/12)\)
\((1/4)\)
Also given that the ratio of the flavoring and water is half -
\((1/2) * (1/30)\)
\((1/60)\)
Hence Sports Formulation:
Flavoring: Corn Syrup : Water
1 : 4 : 60
Now sport formulation contains 3 ounces of corn syrup, hence water is
\((3/4) * 60\)
\(45\) --- Answer choice C.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
