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24 Aug 2017, 23:35
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
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72% (01:47) correct
28%
(01:39)
wrong
based on 69
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In the triangle above, lengths AC and BD are both equal to the same integer. Which of the following could NOT be the area of ∆ ABC?
(A) 1/2
(B) 4 1/2
(C) 6
(D) 8
(E) 12 1/2
Attachment:
2017-08-24_1251_002.png [ 4.37 KiB | Viewed 2355 times ]
24 Aug 2017, 23:43
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If the integer the base and height are equal to is x,
the area for the triangle is \(\frac{1}{2}*x^2 = \frac{x^2}{2}\)
Of the answer options available (after converting the mixed fractions to proper fraction)
(A) \(\frac{1}{2}\)
(B) \(4\frac{1}{2}\) = \(\frac{9}{2}\)
(C) \(6 = \frac{12}{2}\)
(D) \(8 = \frac{16}{2}\)
(E) \(12\frac{1}{2} = \frac{25}{2}\)
The numerator is not a square only in Option C and is our correct answer!
Luckisnoexcuse
Current Student
Joined: 18 Aug 2016
Last visit: 31 Mar 2026
Posts: 510
Own Kudos:
Given Kudos: 198
Concentration: Strategy, Technology
Schools: Kenan-Flagler '20 (M)
GMAT 1: 630 Q47 V29
GMAT 2: 740 Q51 V38
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25 Aug 2017, 00:03
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Bunuel
1/2 is 1/2 * 1^2
9/2 is 1/2 * 3^2
12/2 is 1/2 * not an integer
16/2 is 1/2 * 4^2
25/2 is 1/2 * 5^2
C
