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In the triangle above, lengths AC and BD are both equal to the same in

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In the triangle above, lengths AC and BD are both equal to the same in [#permalink]

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In the triangle above, lengths AC and BD are both equal to the same integer. Which of the following could NOT be the area of ∆ ABC?

(A) 1/2
(B) 4 1/2
(C) 6
(D) 8
(E) 12 1/2

[Reveal] Spoiler:
Attachment:
2017-08-24_1251_002.png
2017-08-24_1251_002.png [ 4.37 KiB | Viewed 237 times ]
[Reveal] Spoiler: OA

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Kudos [?]: 128932 [1], given: 12183

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Re: In the triangle above, lengths AC and BD are both equal to the same in [#permalink]

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New post 24 Aug 2017, 23:43
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If the integer the base and height are equal to is x,
the area for the triangle is \(\frac{1}{2}*x^2 = \frac{x^2}{2}\)

Of the answer options available (after converting the mixed fractions to proper fraction)
(A) \(\frac{1}{2}\)
(B) \(4\frac{1}{2}\) = \(\frac{9}{2}\)
(C) \(6 = \frac{12}{2}\)
(D) \(8 = \frac{16}{2}\)
(E) \(12\frac{1}{2} = \frac{25}{2}\)

The numerator is not a square only in Option C and is our correct answer!
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Re: In the triangle above, lengths AC and BD are both equal to the same in [#permalink]

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New post 25 Aug 2017, 00:03
Bunuel wrote:
Image
In the triangle above, lengths AC and BD are both equal to the same integer. Which of the following could NOT be the area of ∆ ABC?

(A) 1/2
(B) 4 1/2
(C) 6
(D) 8
(E) 12 1/2

[Reveal] Spoiler:
Attachment:
2017-08-24_1251_002.png


1/2 is 1/2 * 1^2
9/2 is 1/2 * 3^2
12/2 is 1/2 * not an integer
16/2 is 1/2 * 4^2
25/2 is 1/2 * 5^2
C
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Kudos [?]: 140 [0], given: 123

Re: In the triangle above, lengths AC and BD are both equal to the same in   [#permalink] 25 Aug 2017, 00:03
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In the triangle above, lengths AC and BD are both equal to the same in

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