Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 27 Oct 2009
Posts: 131
Location: Montreal
Schools: Harvard, Yale, HEC

In Town X, 64 percent of the population are employed, and 48 [#permalink]
Show Tags
16 Nov 2009, 16:25
Question Stats:
57% (01:01) correct 43% (01:09) wrong based on 426 sessions
HideShow timer Statistics
In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? (A) 16% (B) 25% (C) 32% (D) 40% (E) 52%
Official Answer and Stats are available only to registered users. Register/ Login.



VP
Joined: 05 Mar 2008
Posts: 1427

Re: Never underestimate any questions [#permalink]
Show Tags
Updated on: 16 Nov 2009, 17:56
ezinis wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? (A) 16% (B) 25% (C) 32% (D) 40% (E) 52% answer b maleemployed  64% femaleemployed16% Total employed 64% means total unemployed = 36% therefore d and e are not correct because female unemployed has to be less than 36% femaleunemployed = 32% male unemployed = 4% 48% + 4% = 52% 16% + 32% = 48% plug in a and b in place of 32% and the sum is not 100% 16/64 =25
Originally posted by lagomez on 16 Nov 2009, 17:27.
Last edited by lagomez on 16 Nov 2009, 17:56, edited 1 time in total.



Math Expert
Joined: 02 Sep 2009
Posts: 46297

Re: Never underestimate any questions [#permalink]
Show Tags
16 Nov 2009, 17:50



VP
Joined: 05 Mar 2008
Posts: 1427

Re: Never underestimate any questions [#permalink]
Show Tags
16 Nov 2009, 17:57
Bunuel wrote: lagomez wrote: answer C
maleemployed  64% femaleemployed16% Total employed 64%
means total unemployed = 36%
therefore d and e are not correct because female unemployed has to be less than 36%
femaleunemployed = 32% male unemployed = 4% 48% + 4% = 52% 16% + 32% = 48%
plug in a and b in place of 32% and the sum is not 100% I think we are asked to calculate the percentage of females in employed people. Total employed people 64%, out of which 48 are male, hence 16% are employed females. 16/64=1/4=25% Answer: B. made the changes to my original post...you are correct..got the same percentage but i have no idea why i was going for female unemployed..totally off my game. had my mind on something else i guess



Manager
Joined: 13 Aug 2009
Posts: 179

Re: Never underestimate any questions [#permalink]
Show Tags
16 Nov 2009, 23:12
In problems like this one I always like to use tables to organize my thoughts. First I assumed that there are a 100 people in this town (for me it just makes it mentally easier).
.................EMPLOYED........NOT EMPLOYED MALE..............48......................B............. FEMALE...........C.......................D............ TOTALS..........64......................36...............100
We are given the value of Employed + Male = 48 and the value of the Total Employed = 64.
So as we can see it is pretty easy to find the number of Employed + Females: 6448=C or 16.
16/64 = 25%
ANSWER: B.



Manager
Joined: 08 May 2010
Posts: 133

Re: OG12 PS124 [#permalink]
Show Tags
09 May 2010, 21:53
So reading the question very carefully 48% of the population are employed males and 64 % of the population are employed.
What percent of the employed are females? The percent employed females in the total population is easy. That is 16%. 64 minus 48. But they are asking what percent of the employed are female. Now we must compare that 16% to the total employed 16/64. So one quarter of the employed are female.
B) 25% should be correct



Manager
Joined: 16 Feb 2010
Posts: 158

Re: OG12 PS124 [#permalink]
Show Tags
18 May 2010, 16:22
here total employed population is 64% and 48 % of the total population is males so the 16 % of the population is employed is females so the % of females employees out of employed males is( 16/64)*100 = 25%



Senior Manager
Joined: 28 Jun 2009
Posts: 414
Location: United States (MA)

Re: Percentage Population [#permalink]
Show Tags
26 Aug 2010, 08:06
Answer is B.
Lets say the town's population is 100 64 employed (given) 48 employed males (given) 64  48 = 16 employed females
the question is : what percentage of employed ppl are females
therefore,
16 in 64 > how many in 100. Solving... 25



Manager
Joined: 20 Apr 2010
Posts: 186
Schools: ISB, HEC, Said

Re: Percentage Population [#permalink]
Show Tags
27 Aug 2010, 00:23
Question does not seem to have adequate information. Since we dont know how many unempolyed males are there. Solution given by piyatiwari does not cosider this fact. Also would like to know the source of this problem



Senior Manager
Joined: 28 Jun 2009
Posts: 414
Location: United States (MA)

Re: Percentage Population [#permalink]
Show Tags
27 Aug 2010, 05:46
prashantbacchewar wrote: Question does not seem to have adequate information. Since we dont know how many unempolyed males are there. Solution given by piyatiwari does not cosider this fact. Also would like to know the source of this problem We don't need to know number of unemployed males. The question has all the required information. The problem is from OG, I guess.



Manager
Joined: 27 Oct 2009
Posts: 131
Location: Montreal
Schools: Harvard, Yale, HEC

Re: Never underestimate any questions [#permalink]
Show Tags
23 Sep 2010, 07:56
It will be easier if you rephrased the the question like: how many percent female out of the employed people. Most people will jump to answer A (16%) because it accidentally looks like the number they just solved half way. have fun guys.



Senior Manager
Status: Not afraid of failures, disappointments, and falls.
Joined: 20 Jan 2010
Posts: 279
Concentration: Technology, Entrepreneurship
WE: Operations (Telecommunications)

Re: Never underestimate any questions [#permalink]
Show Tags
08 Nov 2010, 23:25
Answer: BExplanation:Suppose, Population= P, Employed People= E , Employed Male= M, and Employed Female= F. What we need to find is \(\frac{Employed Female}{Employed People} %=\frac{F}{E} %\) Let's pick \(100\) as a smart number here for the population of town X. So, \(P= 100\) and \(E= 64% of P = \frac{64}{100} * 100 = 64\) \(M= 48% of P = \frac{48}{100} * 100 = 48\) Then, \(F= E  M = 64  48 = 16\) Therefore, from above we can calculate that, \(\frac{F}{E} % = \frac{16}{64} * 100 = \frac{1}{4} * 100 = 25 %\) (we got what we were asked to find ) Hence the answer is B. Be careful not to get into the trap of finding employed female percentage of population of town X because we are asked to find what percent of the employed people (\(x% of E\)) are female (\(F\)), try to translate the words > \(x% of E = F\) > \(x=F/E %= ?\) and clearly state what exactly needs to be found in your own words or expression.
_________________
"I choose to rise after every fall" Target=770 http://challengemba.blogspot.com Kudos??



Retired Moderator
Joined: 16 Nov 2010
Posts: 1471
Location: United States (IN)
Concentration: Strategy, Technology

Re: Never underestimate any questions [#permalink]
Show Tags
15 Mar 2011, 22:17
Let total population = P and Employed People = E So 0.64P = E and 0.48P = Male So 0.64P  0.48P = 0.16P are employed females So 0.16P/0.64P = 25% So the answer is B.
_________________
Formula of Life > Achievement/Potential = k * Happiness (where k is a constant)
GMAT Club Premium Membership  big benefits and savings



Director
Status: No dream is too large, no dreamer is too small
Joined: 14 Jul 2010
Posts: 545

Re: Never underestimate any questions [#permalink]
Show Tags
15 Mar 2011, 23:04
ezinis wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? (A) 16% (B) 25% (C) 32% (D) 40% (E) 52% Total population 100 total employed 64 employed male 48 (given) employed female 6448= 16 percentage of female employed people to total employed people: 16/64*100=25%
_________________
Collections: PSof OG solved by GC members: http://gmatclub.com/forum/collectionpswithsolutionfromgmatclub110005.html DS of OG solved by GC members: http://gmatclub.com/forum/collectiondswithsolutionfromgmatclub110004.html 100 GMAT PREP Quantitative collection http://gmatclub.com/forum/gmatprepproblemcollections114358.html Collections of work/rate problems with solutions http://gmatclub.com/forum/collectionsofworkrateproblemwithsolutions118919.html Mixture problems in a file with best solutions: http://gmatclub.com/forum/mixtureproblemswithbestandeasysolutionsalltogether124644.html



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1837
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
Show Tags
24 Sep 2014, 23:49
Total Employed (Male + Female) = 64 Male Employed = 48 So, remaining Female employed = 64  48 = 16 Percentage\(= \frac{16}{64} * 100 = 25%\) Answer = B
_________________
Kindly press "+1 Kudos" to appreciate



VP
Status: Learning
Joined: 20 Dec 2015
Posts: 1161
Location: India
Concentration: Operations, Marketing
GRE 1: 314 Q157 V157
GPA: 3.4
WE: Manufacturing and Production (Manufacturing)

Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]
Show Tags
16 Aug 2017, 07:56
ezinis wrote: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
(A) 16% (B) 25% (C) 32% (D) 40% (E) 52% This is a tricky question not because of its difficulty level but because of its wording . We have to find out the percentage of females in employed people . Let the population of town be 100 Total educated people =64 Total educated males =48 Educated females =Total educated people Educated males =644=16 Percentage of females in educated people =16/64=0.25 or 25%
_________________
Please give kudos if you found my answers useful




Re: In Town X, 64 percent of the population are employed, and 48
[#permalink]
16 Aug 2017, 07:56






