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In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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04 Feb 2018, 12:03
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In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 60 sq units, height of the trapezium is 10 units, what is the length of diagonal BD? (A) 10 units (B) \(\sqrt{116}\) units (C) \(5\sqrt{5}\) units (D) \(\sqrt{136}\) units (E) 12 units
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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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04 Feb 2018, 13:24
DHAR wrote: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 60 sq units, height of the trapezium is 10 units, what is the length of diagonal BC?
(A) 10 units
(B) \(\sqrt{116}\) units
(C) \(5\sqrt{5}\) units
(D) \(\sqrt{136}\) units
(E) 12 units Area of Trapezium = \(\frac{1}{2}h(a+b)\) \(a, b = Length of parallel sides.\) \(h = Height between the two parallel sides.\)
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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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07 Feb 2018, 21:28
rahul16singh28 wrote: DHAR wrote: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 60 sq units, height of the trapezium is 10 units, what is the length of diagonal BC?
(A) 10 units
(B) \(\sqrt{116}\) units
(C) \(5\sqrt{5}\) units
(D) \(\sqrt{136}\) units
(E) 12 units Area of Trapezium = \(\frac{1}{2}h(a+b)\) \(a, b = Length of parallel sides.\) \(h = Height between the two parallel sides.\) I can’t visualise how you got to bx=6. Otherwise I just plug in numbers might fit, like a=4 tf b=8 Please help! Sent from my iPhone using GMAT Club Forum mobile app



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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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07 Feb 2018, 21:37
diamund223 wrote: rahul16singh28 wrote: DHAR wrote: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 60 sq units, height of the trapezium is 10 units, what is the length of diagonal BC?
(A) 10 units
(B) \(\sqrt{116}\) units
(C) \(5\sqrt{5}\) units
(D) \(\sqrt{136}\) units
(E) 12 units Area of Trapezium = \(\frac{1}{2}h(a+b)\) \(a, b = Length of parallel sides.\) \(h = Height between the two parallel sides.\) I can’t visualise how you got to bx=6. Otherwise I just plug in numbers might fit, like a=4 tf b=8 Please help! Sent from my iPhone using GMAT Club Forum mobile appHi, \(a + b = 12\) \(a = b  2x.\). Substitute this in the above equation We get, \(2(bx) = 12 > b  x = 6\) Hope, its clear.
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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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08 Feb 2018, 11:48
Thanks! I thought it was an assumption not a solution
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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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06 Jun 2018, 16:30
In a trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 60 sq. units, and height of the trapezium is 10 units, what is the length of diagonal BD?
A. 10 units
B. \(\sqrt{116}\) units
C. 5\(\sqrt{5}\) units
D. \(\sqrt{136}\) units
E. 12 units



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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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06 Jun 2018, 19:50
GMATSkilled wrote: In a trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 60 sq. units, and height of the trapezium is 10 units, what is the length of diagonal BD?
A. 10 units
B. \(\sqrt{116}\) units
C. 5\(\sqrt{5}\) units
D. \(\sqrt{136}\) units
E. 12 units Kindly refer the affixed diagram, Given ABCD and BD=AC(diagonals), hence it's a isosceles trapezium. hence AM=BN. ADM, BNC & DMB are right angled triangles. Given area of trapezium=60 sq unit Or, ½*10(AB+CD)=60 Or, AB+CD=12 Or, X+AM+X+BN=12 Or, 2X+2BN=12 Or, X+BN=6 Or, MB=6 unit Applying Pythagoras theorem in the right angled triangle DMB, we have \(BD^2\)=\(DM^2\)+\(MB^2\)=\(10^2\)+\(6^2\)=136 So, BD=\(\sqrt{136}\) units Ans Option (D)
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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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08 Jun 2018, 02:01



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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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18 Jun 2018, 16:17
DHAR wrote: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 60 sq units, height of the trapezium is 10 units, what is the length of diagonal BC?
(A) 10 units
(B) \(\sqrt{116}\) units
(C) \(5\sqrt{5}\) units
(D) \(\sqrt{136}\) units
(E) 12 units Hi, please correct this. It should be diagonal BD.



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Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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18 Jun 2018, 19:05




Re: In trapezium ABCD, AB  CD and AC = BD. If area of the trapezium is 6
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18 Jun 2018, 19:05






