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01 Aug 2016, 05:51
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D
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Difficulty:
35%
(medium)
Question Stats:
69% (02:08) correct
31%
(02:29)
wrong
based on 98
sessions
History
Date
Time
Result
Not Attempted Yet
In triangle ABC above, if ∠BAD and ∠ADB have measures of 4n°, ∠ACB has a measure of n°, and ∠DBC has a measure of 45°, what is the measure of ∠ABC? (Figure not necessarily drawn to scale.)
A. 45°
B. 60°
C. 90°
D. 105°
E. 120°
Attachment:
2016-08-01_1649.png [ 3.5 KiB | Viewed 5469 times ]
01 Aug 2016, 06:01
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BAD = 4n
ADB = 4n
BDC = 180 - 4n
ACB = n
DBC = 45
BDC + ACB + DBC = 180
180 - 4n + n + 45 = 180
45 = 3n
n = 15
ABD = 180 - (BAD + ADB) = 180 - 120 = 60
ABC = 60 + 45 = 105
Answer: D
ADB = 4n
BDC = 180 - 4n
ACB = n
DBC = 45
BDC + ACB + DBC = 180
180 - 4n + n + 45 = 180
45 = 3n
n = 15
ABD = 180 - (BAD + ADB) = 180 - 120 = 60
ABC = 60 + 45 = 105
Answer: D
16 Aug 2020, 14:06
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Hi all,
I think this is not an overly complicated geometric question as the only general rule that we need to know is that the sum of all angles of a triangle must be 180º, and that the angles over a line is also 180º. Everything is explained and calculated in the below image
ANSWER D
I think this is not an overly complicated geometric question as the only general rule that we need to know is that the sum of all angles of a triangle must be 180º, and that the angles over a line is also 180º. Everything is explained and calculated in the below image
ANSWER D
Attachments
WhatsApp Image 2020-08-16 at 23.05.35.jpeg [ 77.19 KiB | Viewed 3157 times ]
