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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C

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Intern  B
Joined: 17 Jul 2014
Posts: 7
In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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1
8 00:00

Difficulty:   95% (hard)

Question Stats: 32% (02:43) correct 68% (02:43) wrong based on 136 sessions

### HideShow timer Statistics In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C are the vertices of the triangle and a$$^{\circ}$$and b$$^{\circ}$$ denote the angles shown. Is the length of AB greater than that of AC?

(1) a – b = 30

(2) b = 70

Attachment: 100215.jpg [ 9.91 KiB | Viewed 4727 times ]

Originally posted by jyotibrata on 12 Mar 2016, 10:03.
Last edited by ENGRTOMBA2018 on 02 May 2016, 03:40, edited 2 times in total.
Edited the question.
CEO  G
Joined: 20 Mar 2014
Posts: 2544
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44 GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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2
3
jyotibrata wrote:
In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C are the vertices of the triangle and ao and bo denote the angles shown. Is the length of AB greater than that of AC?

(1) a – b = 30

(2) b = 70

Attachment:
The attachment 100215.jpg is no longer available

We can clearly see that in order for getting an answer for is AB>AC we need to find the relation between the angles opposite to this sides as in any triangle the side opposite to a greater angle is greater.

Also, from the property of quadrilaterals, sum of all the angles of a quad = 360 and when used in conjunction with the fact that sum of angles on a triangle = 180 --->

$$\angle {ACB} = a-90$$ (refer to the attached picture to see the calculations).

Attachment: 2016-03-12_13-35-52.jpg [ 12.77 KiB | Viewed 3920 times ]

Per statement 1, a-b=30 ---> a=30+b ---> c = a-90=30+b-90 = b-60 ---> c<b and as sides opposite to greater angles are longer ---> AC>AB

Per statement 2, b=70. Clearly not sufficient.

A is thus the correct answer.

Hope this helps.
##### General Discussion
Manager  Joined: 29 Nov 2011
Posts: 87
Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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Engr2012 wrote:
jyotibrata wrote:
In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C are the vertices of the triangle and ao and bo denote the angles shown. Is the length of AB greater than that of AC?

(1) a – b = 30

(2) b = 70

Attachment:
100215.jpg

We can clearly see that in order for getting an answer for is AB>AC we need to find the relation between the angles opposite to this sides as in any triangle the side opposite to a greater angle is greater.

Also, from the property of quadrilaterals, sum of all the angles of a quad = 360 and when used in conjunction with the fact that sum of angles on a triangle = 180 --->

$$\angle {ACB} = a-90$$ (refer to the attached picture to see the calculations).

Attachment:
2016-03-12_13-35-52.jpg

Per statement 1, a-b=30 ---> a=30+b ---> c = a-90=30+b-90 = b-60 ---> c<b and as sides opposite to greater angles are longer ---> AC>AB

Per statement 2, b=70. Clearly not sufficient.

A is thus the correct answer.

Hope this helps.

Why are you assuming the angle as 90 degree in the triangle you have shown in your figure.
Manager  Joined: 29 Nov 2011
Posts: 87
Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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CEO  G
Joined: 20 Mar 2014
Posts: 2544
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44 GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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1

It's not courteous to post another message without letting the person reply. Do give the OP sufficient time in replying to your question.

I did not assume anything. The question says that the triangle ABC is drawn on the coordinate plane and as such the 2 lines can only be the coordinate axes. Hence, they are perpendicular, making that angle 90 degree

Posted from my mobile device
Manager  Joined: 29 Nov 2011
Posts: 87
Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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Engr2012 wrote:

It's not courteous to post another message without letting the person reply. Do give the OP sufficient time in replying to your question.

I did not assume anything. The question says that the triangle ABC is drawn on the coordinate plane and as such the 2 lines can only be the coordinate axes. Hence, they are perpendicular, making that angle 90 degree

Posted from my mobile device

I apologies , I did not mean that way. I came across few posts from experts where it is clearly written that don't be decisive in DS question with coordinate geometer figures. Thanks for explanation I got your point.
CEO  G
Joined: 20 Mar 2014
Posts: 2544
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44 GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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Engr2012 wrote:

It's not courteous to post another message without letting the person reply. Do give the OP sufficient time in replying to your question.

I did not assume anything. The question says that the triangle ABC is drawn on the coordinate plane and as such the 2 lines can only be the coordinate axes. Hence, they are perpendicular, making that angle 90 degree

Posted from my mobile device

I apologies , I did not mean that way. I came across few posts from experts where it is clearly written that don't be decisive in DS question with coordinate geometer figures. Thanks for explanation I got your point.

You do raise a very valid question, something GMAT question will not do. All GMAT questions are unambiguous (or 99.9% of them) and I'm sure that if this would've been an official question, the question stem would've stated that the vertical and the horizontal lines that make the 90 degrees are the coordinate axes to remove any ambiguity.

Hope this helps.
Intern  B
Joined: 18 Jun 2017
Posts: 1
Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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Sorry I don´t understand why this is not a D.

I think that if I only know the value of B i can Solve de problem.

(180-a) +90 + (180-b) + (180-a) = 360

...
...

2a + b = 270

2) b= 70

----> a= 100 and as a + b+ c = 180 then C= 10 so AC > AB

is that right?
Attachments

File comment: triangle gmatclub.png [ 13.47 KiB | Viewed 2226 times ]

Manager  B
Joined: 19 Feb 2019
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Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  [#permalink]

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Quote:
Also, from the property of quadrilaterals, sum of all the angles of a quad = 360 and when used in conjunction with the fact that sum of angles on a triangle = 180 --->

∠ACB=a−90∠ACB=a−90

Hi can you pls explain how you got a-90 for angle ACB?

I did not get which quadrilateral property you are saying Re: In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C   [#permalink] 01 Dec 2019, 01:11

# In triangle ABC (figure shown) drawn on a coordinate plane, A, B and C  