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  • Typical Day of a UCLA MBA Student - Recording of Webinar with UCLA Adcom and Student

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In year x, it rained on 40% of all Mondays and 20% of all

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VP
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In year x, it rained on 40% of all Mondays and 20% of all  [#permalink]

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New post 08 Aug 2006, 12:26
1
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A
B
C
D
E

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Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 31 sessions

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In year x, it rained on 40% of all Mondays and 20% of all Tuesdays. On what percentage of all the weekdays in year x did it NOT rain?

(1) During year x, it rained on 10% of all Wednesdays.

(2) During year x, it did not rain on 70% of Thursdays and it did not rain on 95% of all Fridays.

please explain

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Senior Manager
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New post 08 Aug 2006, 12:54
IMO C

Because...

52 mondays, tuesdays etc.... in a year

Number of days it did NOT rain:

Monday = 0.6*52
Tuesday = 0.8*52
Wednesday = 0.9*52
Thursday = 0.7*52
Friday = 0.95*52

% No Rain = Number of days it did not rain / Number of total days

Therefore: [(0.6*52)+(0.8*52)+(0.9*52)+(0.7*52)+(0.95*52)]/(52*5)

=79/100 = 79% of the weekdays it did not rain.

You need both statements to capture the information.
Director
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New post 08 Aug 2006, 12:57
Yeah - agree with C.

Each weekday constitutes 20% of the number of days. Calculating, we get no rain on 79% of the weekdays...
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VP
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Re: DS: Rain  [#permalink]

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New post 08 Aug 2006, 13:31
1
u2lover wrote:
In year x, it rained on 40% of all Mondays and 20% of all Tuesdays. On what percentage of all the weekdays in year x did it NOT rain?
(1) During year x, it rained on 10% of all Wednesdays.
(2) During year x, it did not rain on 70% of Thursdays and it did not rain on 95% of all Fridays.
please explain


do we know that the 365th day is weekdays or weekends? do we also know how many days are there in weekdays?

should be E.
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New post 08 Aug 2006, 13:42
1
agsfaltex wrote:
IMO C

Because...

52 mondays, tuesdays etc.... in a year

Number of days it did NOT rain:

Monday = 0.6*52
Tuesday = 0.8*52
Wednesday = 0.9*52
Thursday = 0.7*52
Friday = 0.95*52

% No Rain = Number of days it did not rain / Number of total days

Therefore: [(0.6*52)+(0.8*52)+(0.9*52)+(0.7*52)+(0.95*52)]/(52*5)

=79/100 = 79% of the weekdays it did not rain.

You need both statements to capture the information.


Have you taken the one more day remaining. there are 52 full weeks and one more day and that day can be any day of week. Also we don't know if year x is a leap year or not. If leap year there will be two extra days.

If the answer is NOT E then it is very poorly worded question.
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VP
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New post 08 Aug 2006, 13:51
I was going to go with C until I read Prof's and PS's post....

Maybe it is E... cannot assume weekday is Mon-Fri; Cannot assume X is a leap year or not...
Manager
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New post 08 Aug 2006, 14:16
Is there an official position by GMAT regarding number of days in year?

Also, in some areas the week starts on Sunday...
VP
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New post 08 Aug 2006, 14:25
v1rok wrote:
Is there an official position by GMAT regarding number of days in year?

Also, in some areas the week starts on Sunday...


in the mind of GMAT (GMAT doesn't have a mind... ha-ha), which happens to be written in the US, the work week starts on Monday, but the calendar starts on Sunday... go figure... so this part is overthinking IMO...

however, yes... the problem here is that we don't know if the year X started from weekend or from one of the week days (in that case which week day is also unknown)

OA is E
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New post 08 Aug 2006, 19:33
Exactly, we don't know what the first day of the year was
It is E
We could only calculate an approximation with the available choices.
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Re: In year x, it rained on 40% of all Mondays and 20% of all  [#permalink]

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Re: In year x, it rained on 40% of all Mondays and 20% of all &nbs [#permalink] 05 Aug 2018, 23:10
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