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Inequality.................

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Manager
Joined: 02 Sep 2008
Posts: 103

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27 Apr 2009, 21:07
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10. If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000

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Manager
Joined: 27 Jun 2008
Posts: 155

Kudos [?]: 34 [0], given: 11

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22 Jul 2009, 01:23
Can you please elaborate here, I can't see a correlation between X and Y, X begins at 40 and without restriction it can grow to any value.

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Manager
Joined: 27 Jun 2008
Posts: 155

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22 Jul 2009, 01:24
My Bad, Missed that they are 2 digit integers.

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Manager
Joined: 14 Nov 2008
Posts: 195

Kudos [?]: 129 [0], given: 3

Schools: Stanford...Wait, I will come!!!

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22 Jul 2009, 05:30
milind1979 wrote:
10. If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000

.. The, the number should be either both positive or both negative.
As both negative is not possible, it should be both positive.
Within the constraints, x can be at max 99, and Y can be at max 69.
Multiplying both, D is the answer

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Manager
Joined: 27 Jun 2008
Posts: 155

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22 Jul 2009, 09:08
Yeah, thanks could figure that out.

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Director
Joined: 23 May 2008
Posts: 801

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22 Jul 2009, 10:54
99*69 ~ 100*70= 7000

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Re: Inequality.................   [#permalink] 22 Jul 2009, 10:54
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