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23 Nov 2015, 13:28
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If x and y are two-digit integers such that x > 40 and y < 70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000
PS21237
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000
PS21237
23 Nov 2015, 14:19
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Answer : D
For the value of xy to be maximum, we need to consider maximum value of x and y.
For X, that will be 99 (2 digit integer). For Y, that will be 69 (<70). The value of xy will be 69*99 = (70-1)(100-1) - So less than 7000.
Of all the options available, D satisfies the condition and thus the answer.
For the value of xy to be maximum, we need to consider maximum value of x and y.
For X, that will be 99 (2 digit integer). For Y, that will be 69 (<70). The value of xy will be 69*99 = (70-1)(100-1) - So less than 7000.
Of all the options available, D satisfies the condition and thus the answer.
23 Nov 2015, 19:10
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Bunuel
If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000
(A) 700
(B) 2,800
(C) 4,000
(D) 7,000
(E) 28,000
To get the maximum possible value of xy, we need maximize the value of both x and y
max x can be = 99 (given x is a two-digit integer > 40)
max y can be = 69 (given y is a two-digit integer < 70)
xy = 99*69 = 7000 (approx.)
Answer (D)
