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26 Jul 2012, 13:16
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Hi.
i had an inscribed angle problem asking for the lenght of one of the sides.
the answer was 4 +2rad2.
the answer key says I am supposed to get this by factoring this quadratic y^2 + 8Y + 8 = 0.
how do i do that?
thanks,
Clearmountain
i had an inscribed angle problem asking for the lenght of one of the sides.
the answer was 4 +2rad2.
the answer key says I am supposed to get this by factoring this quadratic y^2 + 8Y + 8 = 0.
how do i do that?
thanks,
Clearmountain
26 Jul 2012, 13:51
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clearmountain
If the answer is \(4+2\sqrt{2}\) then the equation must be \(y^2-8y+8=0\).
You can use the formula which gives the roots of a quadratic equation in terms of its coefficient.
Another way is as follows:
\(y^2-8y+8=y^2-8y+16-8=(y-4)^2-8=0\) from which \((y-4)^2=8\) and either \(y-4=2\sqrt{2}\), so \(y=4+2\sqrt{2}\),
or \(y-4=-2\sqrt{2}\), which gives \(y = 4-2\sqrt{2}\).
28 Jul 2012, 12:14
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clearmountain
Hi Clearmountain,
EvaJager is correct--something must have slipped when you copied this question. After all, y^2 and 8 are both positive. That means that no positive value for y can satisfy the equation, because the sum of three positives will always be greater than 0! Can you double-check the equation and solution that you've posted? I'll be happy to check your math once I've seen what we're really supposed to do.
Regards,
