Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
02 Aug 2018, 11:59
Kudos
Bookmarks
If JKL is a 3 digit number (non zero) and have no zero at any digit place such that
JK is divisible by 9
KL is divisible by 9
Then how many numbers JKL are possible ?
JK is divisible by 9
KL is divisible by 9
Then how many numbers JKL are possible ?
Updated on: 06 Aug 2018, 11:58
Originally posted by MathRevolution on 03 Aug 2018, 08:10.
Last edited by MathRevolution on 06 Aug 2018, 11:58, edited 1 time in total.
Last edited by MathRevolution on 06 Aug 2018, 11:58, edited 1 time in total.
Kudos
Bookmarks
Shahzad hassan
In order for an integer to be a multiple of 9, the sum of all digits is a multiple of 9.
If K = 1, then J = 8 and L = 8.
If K = 2, then J = 7 and L = 7.
If K = 3, then J = 6 and L = 6.
If K = 4, then J = 5 and L = 5.
If K = 5, then J = 4 and L = 4.
If K = 6, then J = 3 and L = 3.
If K = 7, then J = 2 and L = 2.
If K = 8, then J = 1 and L = 1.
If K = 9, then J = 9 and L = 9.
The case of K = 9, J = 0 and L = 0 is not the case we consider, since zero digits are there.
If K = 0, then J = 9 and L = 9, which is not a case we consider, since a zero digit is there.
Thus we have 9 cases.
03 Aug 2018, 10:19
Kudos
Bookmarks
You forgot one possibility of 999 so total of 9 i think
