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Is (1 + 0.01r)(1 - 0.01s) > 1 ? 13 Apr 2018, 01:24
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65% (hard)

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55% (02:21) correct 45% (02:17) wrong based on 83 sessions

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Is \((1 + 0.01r)(1 - 0.01s) > 1\) ?


(1) \(r > s\)

(2) \(0.01rs < r - s\)
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B
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Is (1 + 0.01r)(1 - 0.01s) > 1 ? 13 Apr 2018, 02:35
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Bunuel
Is \((1 + 0.01r)(1 - 0.01s) > 1\) ?


(1) \(r > s\)

(2) \(0.01rs < r - s\)
Show more


\((1 + 0.01r)(1 - 0.01s) > 1............1+0.01r-0.01s-0.0001rs>1...............0.01r-0.01s-0.0001rs>0...............r-s>0.01rs\)

so basically we have to say whether r-s>0.01rs

let's see the statements..
(1) \(r > s\)
just says that r-s>0...
insuff

(2) \(0.01rs < r - s\)
this is exactly what we were looking for..
suff

B
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Is (1 + 0.01r)(1 - 0.01s) > 1 ? 13 Apr 2018, 22:15
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Hello chetan2u,
(1+0.01r)(1−0.01s)=1+.01[(r-s)-0.01rs]
If we will take r<s
Suppose r=10 s=20
Then 1+.01[(r-s)-0.01rs]=0.88
And if r=20 and s=10
Then 1+.01[(r-s)-0.01rs]=1.08
Hence option c is correct
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Is (1 + 0.01r)(1 - 0.01s) > 1 ? 13 Apr 2018, 22:21
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GYANENDRA88
Hello chetan2u,
(1+0.01r)(1−0.01s)=1+.01[(r-s)-0.01rs]
If we will take r<s
Suppose r=10 s=20
Then 1+.01[(r-s)-0.01rs]=0.88
And if r=20 and s=10
Then 1+.01[(r-s)-0.01rs]=1.08
Hence option c is correct
Show more


\(0.01rs<r−s\)...
if r = 10 and s = 20..
\(0.01*10*20 <10-20.......2<-10\)????.... not valid as per statement II
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Is (1 + 0.01r)(1 - 0.01s) > 1 ? 27 Apr 2018, 22:45
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Resolving equation

1+0.01[(r-s)-0.1rs]

I) r>s

3>2 value of equation less than 1
3>-2 value of equation greater then 1
Insufficient

II)this equation makes bracket greater than 1 in equation
So value >1
Sufficient

B is answer

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Is (1 + 0.01r)(1 - 0.01s) > 1 ? 07 Jun 2018, 06:23
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Bunuel chetan2u

Can you please elaborate how 1 is insufficient
On solveing the given equation we get
r-s>0.01rs
in this equation if we take any value of r greater than s it satisfy the above equation.
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Is (1 + 0.01r)(1 - 0.01s) > 1 ? 07 Jun 2018, 09:51
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Bunuel chetan2u

Can you please elaborate how 1 is insufficient
On solveing the given equation we get
r-s>0.01rs
in this equation if we take any value of r greater than s it satisfy the above equation.
Show more


No it does not..
Take huge value for r and s but very less difference between the two..
Say r=100 and s=99...
So r-s=100-99=1..
But 0.01rs=0.01*100*99=99..
Here r-s<0.01rs as 1<99
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