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Is 3x^2 - 2 > 0?

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Re: Is 3x^2 - 2 > 0? [#permalink]
lpetroski wrote:
chetan2u wrote:
fattty wrote:
Is 3x^2 - 2 > 0?

(1) x < 4
(2) x > -3

Hi,
as usual , lets see the inequality and get some info out of it..
$$3x^2 - 2 > 0$$..
or $$x^2>\frac{2}{3}$$..
Now this to be true, x can not lie between $$\sqrt{\frac{2}{3}}$$ and $$-\sqrt{\frac{2}{3}}$$

Lets see the statements now..
(1) x < 4
this range includes both x in between $$\sqrt{\frac{2}{3}}$$ and $$-\sqrt{\frac{2}{3}}$$ and x outside it... insuff

(2) x > -3
again this range includes both x in between $$\sqrt{\frac{2}{3}}$$ and $$-\sqrt{\frac{2}{3}}$$ and x outside it... insuff

combined.. the above point still remains.. insuff

E

hi! I've just put 2 conditions -

Statement 1 - x < 4

x could = -1 and answer would be yes
or
x = 0 and answer is no

These numbers work for statement 2 as well, thus E.

Is that logic right?

Hi,
you are correct..
if you pick up two numbers in the range , each giving different answers yes and no....
the outcome will be that the statement is not sufficient..
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Re: Is 3x^2 - 2 > 0? [#permalink]
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Re: Is 3x^2 - 2 > 0? [#permalink]
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