Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1310:00 AM EST
-12:00 PM EST
Have you ever wondered how to score a PERFECT 805 on the GMAT? Meet Julia, a banking professional who used the Target Test Prep course to achieve this incredible feat. Julia's story is nothing short of an inspiration.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
Dec 1411:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- Dec 15
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
10 Sep 2017, 21:53
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
58% (01:49) correct
42%
(02:06)
wrong
based on 100
sessions
History
Date
Time
Result
Not Attempted Yet
10 Sep 2017, 23:05
Kudos
Bookmarks
Bunuel
Is \(\sqrt{6a + x^2} = a + x\)?
(1) x = 0
(2) a = 2
(1) x = 0
(2) a = 2
Individually the statements are not going to be enough to prove
if \(\sqrt{6a + x^2} = a + x\)
as statement 1 contains the value of x and statement 2 contains the value of a
However, on combining the information from both the statements, we can clearly find out
that the equation \(\sqrt{6a + x^2} = a + x\) is not true. (Sufficient) (Option C)
18 Sep 2017, 20:01
Kudos
Bookmarks
But,
If a =2, then sqrt(6(2)+x) = 2+x
If you square both sides, 12+x^2 = 4+4x+x^2
subtract x^2, 12=4+4x
Thus, x =2.
So why can't the answer be just b?
Individually the statements are not going to be enough to prove
if \(\sqrt{6a + x^2} = a + x\)
as statement 1 contains the value of x and statement 2 contains the value of a
However, on combining the information from both the statements, we can clearly find out
that the equation \(\sqrt{6a + x^2} = a + x\) is not true. (Sufficient) (Option C)
If a =2, then sqrt(6(2)+x) = 2+x
If you square both sides, 12+x^2 = 4+4x+x^2
subtract x^2, 12=4+4x
Thus, x =2.
So why can't the answer be just b?
pushpitkc
Bunuel
Is \(\sqrt{6a + x^2} = a + x\)?
(1) x = 0
(2) a = 2
(1) x = 0
(2) a = 2
Individually the statements are not going to be enough to prove
if \(\sqrt{6a + x^2} = a + x\)
as statement 1 contains the value of x and statement 2 contains the value of a
However, on combining the information from both the statements, we can clearly find out
that the equation \(\sqrt{6a + x^2} = a + x\) is not true. (Sufficient) (Option C)
