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Given , 7 + x / 8 + x = > 7 /8 ?
At first we need to completely simplify the above equation by bringign the entire equation to one side.
Fianlly we get the equation as x / 8 x + 64 => 0 ?

Statement 1: x <= 0
Putting x as 0 we can get 0 /64 = 0
now putting x as -1 we get (-1/ 56) which is less than 0
Hence the statement has two contrasting values.
Not sufficient.

Statement 2 : x => 0
putting x = 0
we are getting 0/ 64 = 0
putting x as 1, we are still getting a positive number which is greater than 0
Hence sufficient

IMO B
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Is \(\frac{7+x}{8+x} ≥ \frac{7}{8}\)?

The question transforms to: is \(\frac{x}{x+8}\geq{0}\). This equation will hold true for \(x<-8\) and \(x\geq{0}\)

(1) \(x \leq 0\). Not sufficient.
(2) \(x \geq 0\). Sufficient.

Answer: B.
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