sasidharrs wrote:

Hi,

Why B is not sufficient.. given a/b<1 => a<b.. which is what we are trying to prove right.. or am I missing something more fundamental in inequalities?

Hi

In case of inequalities, you cannot multiply or divide both sides by a variable until and unless you know the sign of that variable (positive or negative)

So if you are given: a/b < 1 you will have to take both the cases:

Case 1. b is positive. In this case, we will multiply both sides by b, and since b is positive, the sign of inequality will Not change. So

a/b * b < 1*b or a < b

Case 2. b is negative. In this case, we will multiply both sides by b, and since b is negative, the sign of inequality Will change. So

a/b * b > 1*b or a > b

Hope this helps