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18 Nov 2004, 19:19
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Is a< b?
1) a divided by b has the remainder 8
2) b divided by a has the remainder 7
1) a divided by b has the remainder 8
2) b divided by a has the remainder 7
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19 Nov 2004, 04:06
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Maybe I 100% misunderstood the stem but I would choose E.
We are not speaking about integers here is it obvious as beneath the statements stand divisor and remainder ?
Agree that statements 1 and 2 alone does not bring anything as we can have a = 10b+c or a=0b+c, this is symmetrical.
if we consider 2 statements together :
a = Xb+8 and b=Ya+7 and after some (maybe flawed calculations) I obtain b/a = (8Y+7)/(8-7X)
if Y=X=0, a>b, if Y and X=another mixed values, a<b
We are not speaking about integers here is it obvious as beneath the statements stand divisor and remainder ?
Agree that statements 1 and 2 alone does not bring anything as we can have a = 10b+c or a=0b+c, this is symmetrical.
if we consider 2 statements together :
a = Xb+8 and b=Ya+7 and after some (maybe flawed calculations) I obtain b/a = (8Y+7)/(8-7X)
if Y=X=0, a>b, if Y and X=another mixed values, a<b
19 Nov 2004, 06:27
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Will go with E.
1)--- a=bx+8, where x= any integer.
plug in b=1, x=-5, 0, 5 etc. statement 1 is insuff.
2) b=ax+7, where x= any integer.
plug in a=1, x=-5, 5, 5 etc.. statement 2 is insuff.
combinign also, we dont get any result.
1)--- a=bx+8, where x= any integer.
plug in b=1, x=-5, 0, 5 etc. statement 1 is insuff.
2) b=ax+7, where x= any integer.
plug in a=1, x=-5, 5, 5 etc.. statement 2 is insuff.
combinign also, we dont get any result.
