Is |a| + |b| |a + b| ? (1) a^2 b^2 (2) |a| b

Question

Is |a| + |b| > |a + b| ? 

(1) a^2 > b^2

(2) |a| Ã— b < 0

please explain

v1rok · Answer

I've got (E) ST1. a^2>b^2 Case1: a=2,b=1 => 3=3 Case2: a=2,b=-1 => 3>1 Not SUFF ST2. |a|b<0 => b<0 Still not suff Case1: a=1,b=-1 Case2: a=-1,b=-1 Combining, still not suff Case1: a=2,b=-1 Case2: a=-2,b=-1 So, (E)

Professor · Answer

E. we donot know the signs of a and b.

jamesrwright3 · Answer

E ...

ps_dahiya · Answer

Must be E. Signs of both a and b are required. Statement 2 tells only the sign of b. Statement 1 just tells that a=b is false.

ivymba · Answer

Isn't the answer B ?

Please correct me if I am wrong

Stmt 2
(1) a^2 > b^2 InSufficient

(2) |a| Ã— b < 0

Lets assume a is +ve
Then we get ab < 0 , Since a is +ve , b must be negative for the condition to be true

Now lets assume a -ve
then we get -ab<0 , Since a is negative , b must + ve for the condition to be true

Since a and b are opposite signs
|a| + |b| > |a + b|
try with 2,-3
|-2| + |3| > |-2 + 3|

or -2,3
|2| + |-3| > |2 - 3|

sgrover · Answer

If a is -ve, then |a| is +ve .. The 2nd statement tells us that b is -ve, but no information can be deduced abt a.

jaynayak · Answer

E

1) when a = 3 and b = 2
then |a| + |b| = |a+b|

When a = -3 and b = 2
then |a| + |b| > |a+b|

Not suff

2) b is negative.
When a = 3 and b = -2 
then |a| + |b| > |a+b|
when a = -3 and b = -2
then |a| + |b| = |a+b|
Not suff

Together
Same as 2. Not suff.

baski6 · Answer

St 1 tells no sign for a and b.
St 2 tells sign for only b

E

FN · Answer

yup...E we dont know the sign of a

Is |a| + |b| > |a + b| ? (1) a^2 > b^2 (2) |a| b <

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