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Vamshi8411
Joined: 24 Jul 2012
Last visit: 20 Oct 2013
Posts: 12
Given Kudos: 7
Schools: Schulich '16
GMAT 1: 610 Q49 V26
WE:Consulting (Consulting)
17 Sep 2012, 05:50
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (01:54) correct
33%
(01:33)
wrong
based on 381
sessions
History
Date
Time
Result
Not Attempted Yet
17 Sep 2012, 08:53
Kudos
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Is A multiple of 6?
(1) A = B(B+4)(B-4). If \(B=odd\), then \(A=B(B+4)(B-4)=odd*odd*odd=odd\) and the answer is NO but if \(B=6\), then the answer is obviously YES. Not sufficient.
(2) B-4 is a multiple of 3. B is 4 more than a multiple of 3. Not sufficient, since no info about A.
(1)+(2) From (2) we have that B is 4 more than a multiple of 3 and from (1) that \(A=B(B+4)(B-4)\). If \(B=odd\) (for example if \(B=7\)), then the answer is NO but if \(B=4\), then \(A=B(B+4)(B-4)=0\) and the answer is YES (since zero is a multiple of all integers). Not sufficient.
Answer: E.
Hope it helps.
(1) A = B(B+4)(B-4). If \(B=odd\), then \(A=B(B+4)(B-4)=odd*odd*odd=odd\) and the answer is NO but if \(B=6\), then the answer is obviously YES. Not sufficient.
(2) B-4 is a multiple of 3. B is 4 more than a multiple of 3. Not sufficient, since no info about A.
(1)+(2) From (2) we have that B is 4 more than a multiple of 3 and from (1) that \(A=B(B+4)(B-4)\). If \(B=odd\) (for example if \(B=7\)), then the answer is NO but if \(B=4\), then \(A=B(B+4)(B-4)=0\) and the answer is YES (since zero is a multiple of all integers). Not sufficient.
Answer: E.
Hope it helps.
General Discussion
Pansi
Joined: 04 Jul 2011
Last visit: 01 Dec 2019
Posts: 42
Given Kudos: 87
Status:Fighting hard
Schools: Kellogg '15 ISB '14 (S)
GMAT Date: 10-01-2012
17 Sep 2012, 06:01
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Is A =6K ?
Statement 1 - A = (B-4)(B)(B+4)
B= 4, A =0 ----> No, A is not a multiple of 6
B= 6, A =(2)(6)(10) -----> Yes, A is a multiple of 6
Statement 2 - B is a multiple of 3 - B has no relationship with A.
Combined Statement 1 + Statement 2
B=6, As seen above "A" is a multiple of 6
B=9, A =(5)(9)(13) ----> No, A is not a multiple of 6
Answer is E
Statement 1 - A = (B-4)(B)(B+4)
B= 4, A =0 ----> No, A is not a multiple of 6
B= 6, A =(2)(6)(10) -----> Yes, A is a multiple of 6
Statement 2 - B is a multiple of 3 - B has no relationship with A.
Combined Statement 1 + Statement 2
B=6, As seen above "A" is a multiple of 6
B=9, A =(5)(9)(13) ----> No, A is not a multiple of 6
Answer is E
