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23 May 2018, 08:39
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
66% (01:25) correct
34%
(02:01)
wrong
based on 82
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(ab < 9\) ?
(1) \(a < 2\) and \(b < 4\)
(2) \(\frac{1}{5} < a < \frac{3}{4}\) and \(b^2 < 121\)
(1) \(a < 2\) and \(b < 4\)
(2) \(\frac{1}{5} < a < \frac{3}{4}\) and \(b^2 < 121\)
23 May 2018, 10:47
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Is \(ab < 9\) ?
(1) \(a < 2\) and \(b < 4\)
Here We can have (a,b) = (1,3); ab = 3<4
or (a,b) = (-4,-10); ab = 40 >9
NOT SUFFICIENT
(2) \(\frac{1}{5} < a < \frac{3}{4}\) and \(b^2 < 121\)[/quote]
here \(\frac{1}{5} < a < \frac{3}{4}\) and -11<b<11
So max value of ab = \(\frac{3}{4}\)*11 = 8.25 <9
hence SUFFICIENT
Answer B
(1) \(a < 2\) and \(b < 4\)
Here We can have (a,b) = (1,3); ab = 3<4
or (a,b) = (-4,-10); ab = 40 >9
NOT SUFFICIENT
(2) \(\frac{1}{5} < a < \frac{3}{4}\) and \(b^2 < 121\)[/quote]
here \(\frac{1}{5} < a < \frac{3}{4}\) and -11<b<11
So max value of ab = \(\frac{3}{4}\)*11 = 8.25 <9
hence SUFFICIENT
Answer B
18 Feb 2022, 12:32
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