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14 Jun 2023, 06:00
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A
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Difficulty:
15%
(low)
Question Stats:
91% (01:12) correct
9%
(01:35)
wrong
based on 34
sessions
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14 Jun 2023, 06:08
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S1) n(n+2) is even
If n= odd, then n+2 will also be odd, and odd * odd can never be even
Hence, n = even and n+2 is also even.
S2) n(n+3) is even
If n = odd, n+3 is even (since, odd + odd is even) hence n = odd;
But if n = even, n+3 = odd, then n(n+3) is even, hence n = even
SO S1) is suff.
Answer A
If n= odd, then n+2 will also be odd, and odd * odd can never be even
Hence, n = even and n+2 is also even.
S2) n(n+3) is even
If n = odd, n+3 is even (since, odd + odd is even) hence n = odd;
But if n = even, n+3 = odd, then n(n+3) is even, hence n = even
SO S1) is suff.
Answer A
